CBSE Class 10 Science 2025 — Paper 31/S/2
80 marks · 3 hours · 39 questions (45 with the OR choices)
32 of its 45 questions also appear in 31/S/1 or 31/S/3; 13 are only in this paper.
Take this paper as a timed mock
Free with an account: the board's time limit, marking at the end, and the answer to every question.
Questions 1–20 · 1 mark each
- Q1 1 mark
Also in 31/S/1 (Q8), 31/S/3 (Q6)
Application of Abscisic acid on plants promotes :- (a)Development of fruits
- (b)Wilting of leaves
- (c)Elongation of stem
- (d)Formation of flowers
Step-by-step solution →Show answer
(b) Wilting of leaves - Q2 1 mark
Also in 31/S/1 (Q7), 31/S/3 (Q8)
The part of the hindbrain present immediately above the medulla is :- (a)Cerebellum
- (b)Pons
- (c)Cerebrum
- (d)Spinal cord
Step-by-step solution →Show answer
(b) Pons - Q3 1 markConsider the following cases :
- (i)
- (ii)
- (iii)
- (iv) The cases in which new products will form, are :
- (a)(i) and (ii)
- (b)(ii) and (iv)
- (c)(iii) and (iv)
- (d)(ii) and (iii)
Step-by-step solution →Show answer
(b) (ii) and (iv) - Q4 1 markThe number of single and double bonds present in a molecule of benzene () respectively, are :
- (a) and
- (b) and
- (c) and
- (d) and
Step-by-step solution →Show answer
(d) and - Q5 1 mark
Also in 31/S/1 (Q3)
The most malleable metals are :- (a)Iron and gold
- (b)Copper and silver
- (c)Silver and gold
- (d)Gold and copper
Step-by-step solution →Show answer
(c) Silver and gold - Q6 1 markBreakdown of proteins in the stomach takes place by the enzyme :
- (a)Trypsin
- (b)Lipase
- (c)Salivary Amylase
- (d)Pepsin
Step-by-step solution →Show answer
(d) Pepsin - Q7 1 mark
Also in 31/S/1 (Q2)
Select exothermic processes from the following :- (i)Dilution of acid
- (ii)Burning of natural gas
- (iii)Evaporation of water
- (iv)Electrolysis of water
- (a)(i) and (ii)
- (b)(ii) and (iii)
- (c)(iii) and (iv)
- (d)(i) and (iv)
Step-by-step solution →Show answer
(a) (i) and (ii) - Q8 1 mark
Also in 31/S/1 (Q1), 31/S/3 (Q4)
From the following, select a process in which combination reaction occurs :- (a)Black and white photography
- (b)Burning of carbon (coal)
- (c)Burning of methane
- (d)Refining of copper
Step-by-step solution →Show answer
(b) Burning of carbon (coal) - Q9 1 markThe unit of heredity is :
- (a)Chromosome
- (b)Chromatin
- (c)Gene
- (d)DNA
Step-by-step solution →Show answer
(c) Gene - Q10 1 mark
Also in 31/S/1 (Q9), 31/S/3 (Q10)
The end product of meiosis in a reproductive cell in plants is :- (a)Zygote
- (b)Pollen grains
- (c)Sperms
- (d)Egg
Step-by-step solution →Show answer
(b) Pollen grains - Q11 1 mark
Also in 31/S/1 (Q16)
Which one of the following statements is incorrect about the effect on our environment as a result of our activities ?- (a)Improvement in our lifestyle has resulted in greater amounts of waste.
- (b)Packaging of materials has resulted in lesser amount of non-biodegradable waste.
- (c)Use of disposable cups/kulhads results in loss of fertile topsoil.
- (d)Harmful wastes that are non-biodegradable persist in the environment for a long time.
Step-by-step solution →Show answer
(b) Packaging of materials has resulted in lesser amount of non-biodegradable waste. - Q12 1 mark
Also in 31/S/1 (Q15), 31/S/3 (Q11)
The organism occupying the fourth trophic level in a food chain operating in grassland is :- (a)Green plants
- (b)Frog
- (c)Grasshopper
- (d)Snake
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(d) Snake - Q13 1 mark
Also in 31/S/1 (Q14), 31/S/3 (Q12)
The strength of the magnetic field inside a current carrying long straight solenoid is :- (a)maximum at its centre.
- (b)minimum at its centre.
- (c)maximum at the ends and minimum at its centre.
- (d)uniform throughout its length.
Step-by-step solution →Show answer
(d) uniform throughout its length. - Q14 1 mark
Also in 31/S/1 (Q13), 31/S/3 (Q14)
Which one of the following factors affects the electrical resistivity of a conductor ?- (a)Temperature
- (b)Length
- (c)Shape
- (d)Thickness
Step-by-step solution →Show answer
(a) Temperature - Q15 1 mark
Also in 31/S/1 (Q12), 31/S/3 (Q13)
An optical device which always produces images of is :- (a)Plane mirror
- (b)Convex mirror
- (c)Concave mirror
- (d)Convex lens
Step-by-step solution →Show answer
(a) Plane mirror - Q16 1 markRefractive index of diamond with respect to glass is . If the absolute refractive index of glass is , the absolute refractive index of diamond is :
- (a)
- (b)
- (c)
- (d)
Step-by-step solution →Show answer
(c) - Q17 1 mark
Also in 31/S/1 (Q20), 31/S/3 (Q19)
Two statements are given below — one labelled as Assertion (A) and the other labelled as Reason (R). Select the correct answer to this question from the codes (a), (b), (c) and (d) as given below.Assertion (A): Due to scattering of sunlight, the clear sky predominantly appears blue.
Reason (R): The wavelength of blue light is nearly times the wavelength of red light.
- (a)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
- (b)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
- (c)Assertion (A) is true, but Reason (R) is false.
- (d)Assertion (A) is false, but Reason (R) is true.
Step-by-step solution →Show answer
(c) Assertion (A) is true, but Reason (R) is false. - Q18 1 mark
Also in 31/S/1 (Q19), 31/S/3 (Q17)
Two statements are given below — one labelled as Assertion (A) and the other labelled as Reason (R). Select the correct answer to this question from the codes (a), (b), (c) and (d) as given below.Assertion (A): In our homes we receive supply of electric power through a main supply. One of the wires in this supply, usually with red insulation, is called live wire and another wire with green insulation is called neutral wire.
Reason (R): In our country, the potential difference between the live wire and the neutral wire is 220 volts.
- (a)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
- (b)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
- (c)Assertion (A) is true, but Reason (R) is false.
- (d)Assertion (A) is false, but Reason (R) is true.
Step-by-step solution →Show answer
(d) Assertion (A) is false, but Reason (R) is true. - Q19 1 mark
Also in 31/S/1 (Q17), 31/S/3 (Q18)
Two statements are given below — one labelled as Assertion (A) and the other labelled as Reason (R). Select the correct answer to this question from the codes (a), (b), (c) and (d) as given below.Assertion (A): Decomposition of vegetable matter into compost is an exothermic reaction.
Reason (R): Decomposition reactions need energy to break down the reactants.
- (a)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
- (b)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
- (c)Assertion (A) is true, but Reason (R) is false.
- (d)Assertion (A) is false, but Reason (R) is true.
Step-by-step solution →Show answer
(b) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A). - Q20 1 mark
Also in 31/S/1 (Q18), 31/S/3 (Q20)
Two statements are given below — one labelled as Assertion (A) and the other labelled as Reason (R). Select the correct answer to this question from the codes (a), (b), (c) and (d) as given below.Assertion (A): Transpirational pull helps in the absorption and upward movement of water and dissolved minerals in plants.
Reason (R): The effect of root pressure in transport of water is more significant at night.
- (a)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
- (b)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
- (c)Assertion (A) is true, but Reason (R) is false.
- (d)Assertion (A) is false, but Reason (R) is true.
Step-by-step solution →Show answer
(b) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
Questions 21–26 · 2 marks each
- Q21(a) 2 marks
Also in 31/S/1 (Q22(a)), 31/S/3 (Q23(a))
- (i)What is an alloy ?
- (ii)Write the composition of solder and the property which makes it suitable for welding electric wires.
Step-by-step solution →Show answer
An alloy is a homogeneous mixture of metals; solder is lead and tin, and its low melting point suits welding wires.
(i) An alloy is a homogeneous mixture of two or more metals, or of a metal and a non-metal. (ii) Solder is an alloy of lead and tin taken in roughly equal amounts, about Pb and Sn; its very low melting point — lower than that of either lead or tin — is the property that makes it suitable for welding electric wires.ORQ21(b) 2 marksAlso in 31/S/1 (Q22(b)), 31/S/3 (Q23(b))
During electrolytic refining of silver :- (i)What are the electrodes – cathode and anode made up of ?
- (ii)What is anode mud ? Why is it called so ?
Step-by-step solution →Show answer
Anode is impure silver and cathode is pure silver; anode mud is the insoluble noble-metal impurity that settles below the anode.
(i) The anode is a thick block of impure silver and the cathode is a thin strip of pure silver, dipped in a solution of a silver salt such as acidified silver nitrate. (ii) Anode mud is the insoluble impurities — noble metals such as gold and platinum — which do not dissolve in the electrolyte and settle down at the bottom, just below the anode; it is called anode mud because it collects beneath the anode as a mud-like deposit. - Q22 2 marks
Also in 31/S/1 (Q21), 31/S/3 (Q22)
Translate the following statements into balanced chemical equations :- (a)Aluminium reacts with copper chloride to form aluminium chloride and copper.
- (b)Zinc reacts with sodium hydroxide to give sodium zincate and hydrogen gas.
Step-by-step solution →Show answer
The balanced equations are and .
(a) ; (b) - Q23 2 marksHow is the small intestine in humans designed to absorb the digested food ?Step-by-step solution →
Show answer
It is a long, coiled tube whose villi increase the absorbing surface, and their blood vessels carry the food to every cell.
The small intestine is designed for absorption in these ways. (1) Its inner lining has numerous finger-like projections called villi, which increase the surface area for absorption. (2) The villi are richly supplied with blood vessels, which take the absorbed food to each and every cell of the body. (3) It is a very long, coiled tube, so the digested food passes over a large area of lining. In each villus a lymph vessel, the lacteal, also takes up absorbed fat. - Q24 2 marks
Also in 31/S/1 (Q26), 31/S/3 (Q21)
Draw a ray diagram to show the path of a ray of light which falls obliquely on one of the faces of an equilateral triangular prism made of glass and mark on it the angle of incidence () and the angle of deviation ().Step-by-step solution →Show answer
The ray bends towards the normal at and away at , giving angle of deviation for .
The ray diagram is shown in the figure. The ray strikes the face obliquely, bends towards the normal on entering the glass, travels across the prism, and bends away from the normal as it emerges from the face , so it is deviated towards the base. The angle of incidence is marked between the incident ray and the normal at the first face, and the angle of deviation is marked between the incident ray produced forward and the emergent ray. For the case drawn, and with , so . - Q25 2 marks
Also in 31/S/1 (Q25)
An object is placed cm in front of a concave mirror of focal length cm. Use mirror formula and new cartesian sign convention to determine the position of the image formed.Step-by-step solution →Show answer
cm: the image is formed 37.5 cm in front of the mirror, real, inverted and enlarged.
cm — the image is formed cm in front of the mirror, on the same side as the object. It is real, inverted and enlarged, with . - Q26(a) 2 marks
Also in 31/S/1 (Q24(a)), 31/S/3 (Q26(a))
Explain how tendrils help a pea plant climb up other plants or fences.Step-by-step solution →Show answer
The part of a tendril touching a support grows more slowly, so the tendril coils round it and anchors the weak stem.
Tendrils are thin thread-like growths of the stem that are sensitive to touch. When a tendril meets a support, the part of the tendril in contact with the object grows more slowly than the part away from it. This unequal growth makes the tendril bend towards the support, circle around it and cling to it. The coils anchor the weak stem, so the pea plant is held up and can climb another plant or a fence.ORQ26(b) 2 marksAlso in 31/S/1 (Q24(b)), 31/S/3 (Q26(b))
List two major limitations of the use of electrical impulses as a means of communication between the cells in most multicellular animals.Step-by-step solution →Show answer
Impulses reach only cells joined by nervous tissue, and a cell needs time to reset before it can send another impulse.
(i) Electrical impulses reach only those cells that are connected by nervous tissue, and not each and every cell of the animal body. (ii) After a cell has generated and transmitted an impulse it needs time to reset its mechanisms before it can send another, so cells cannot continually create and transmit electrical impulses. These limitations are why most multicellular animals also use chemical communication.
Questions 27–33 · 3 marks each
- Q27 3 marks
Also in 31/S/1 (Q33), 31/S/3 (Q32)
- (a)Define the term biological magnification.
- (b)In the given aquatic food chain, which trophic level will have highest effect of biological magnification and why ? Phytoplankton Zooplankton Fishes Human
Step-by-step solution →Show answer
Biological magnification is the progressive rise of harmful chemicals along a food chain; it is highest in human beings, the last level.
(a) Biological magnification is the progressive increase in the concentration of harmful non-biodegradable chemicals, such as pesticides, at each successive trophic level of a food chain. (b) In the given chain the highest effect of biological magnification will be at the last trophic level, that is in Human beings, the fourth trophic level. The reason is that these chemicals cannot be broken down or excreted, so they are stored in the body of every organism that takes them in. At each step an organism eats a large number of organisms of the level below, so almost all the chemical stored in them is collected into one body, while only about ten per cent of the biomass is passed on. The concentration therefore multiplies at every step and is greatest in the organism at the end of the chain. - Q28 3 marksYou have two solutions ‘X’ and ‘Y’. ‘X’ gives red colour and ‘Y’ gives blue colour with universal indicator.
- (a)In which solution is the hydrogen ion concentration more than the other ? Give reason to justify your answer.
- (b)If ‘X’ and ‘Y’ are mixed in proper amounts and the resultant mixture of ‘X’ and ‘Y’, with the universal indicator turns green, what would be the nature of the resultant mixture ? Justify your answer.
Step-by-step solution →Show answer
X has the higher hydrogen ion concentration (low pH); the green mixture is neutral (pH 7).
(a) Solution X has the higher hydrogen ion concentration. Red with universal indicator means a low pH, so X is strongly acidic, while blue means that Y is basic, with a pH above 7; the higher the hydrogen ion concentration, the lower the pH. (b) The resultant mixture is neutral. Green with universal indicator corresponds to pH 7: when the acid X and the base Y are mixed in proper amounts they neutralise each other, the hydrogen ions of the acid combining with the hydroxide ions of the base to form water, , so neither is left in excess. - Q29 3 marksName the parts ‘X’ and ‘Y’ of human brain in the given diagram and give one function of each.
Median section of the human brain with two parts marked ‘X’ and ‘Y’. Step-by-step solution →Show answer
X is the medulla, controlling involuntary actions; Y is the cerebellum, giving posture, balance and precision to voluntary actions.
‘X’ is the medulla (medulla oblongata) of the hind-brain. Function: it controls involuntary actions such as blood pressure, salivation and vomiting. ‘Y’ is the cerebellum of the hind-brain. Function: it is responsible for the precision of voluntary actions and for maintaining the posture and balance of the body. - Q30 3 marks
Also in 31/S/1 (Q27), 31/S/3 (Q28)
- (a)Write the name and chemical formula of a sodium compound which is sometimes added for faster cooking. How is it produced from sodium chloride as one of the raw materials ? Give chemical equation for the reaction involved.
- (b)The compound mentioned in (a) above is also an ingredient of antacids. Why ?
Step-by-step solution →Show answer
Sodium hydrogencarbonate, , is made from brine, ammonia and carbon dioxide; being a mild base, it neutralises excess stomach acid.
(a) The compound is sodium hydrogencarbonate, or baking soda, formula . It is made from brine by saturating the sodium chloride solution with ammonia and then passing carbon dioxide through it: ; the sparingly soluble sodium hydrogencarbonate separates out. (b) It is an ingredient of antacids because it is a mild, non-corrosive base and therefore neutralises the excess hydrochloric acid in the stomach, raising the pH and relieving the acidity: . - Q31 3 marks
- (a)State the Right-hand thumb rule.
- (b)A steady current flows through a horizontal power line from east to west direction as shown in the figure. Apply right-hand thumb rule to determine the direction of magnetic field (i) at a point directly below it, and (ii) at a point directly above it.
Compass directions, and the power line with an arrow pointing towards W. Step-by-step solution →Show answer
Below the wire the field points south; above the wire it points north.
(a) Right-hand thumb rule: imagine holding a current-carrying straight conductor in your right hand so that the thumb points in the direction of the current; then the fingers wrapped around the conductor point in the direction of the field lines of the magnetic field. (b) Looking along the power line from its east end, the current flows away from the observer, so by the rule the field lines circle the wire clockwise; facing west, north is on the observer's right. (i) At a point directly below the wire the magnetic field is directed towards the south, from north to south. (ii) At a point directly above the wire it is directed towards the north, from south to north. - Q32 3 marks
Also in 31/S/1 (Q31)
Show the arrangement of three resistors of , and which are connected in such a way that the total/equivalent resistance of the combination is- (a), and
- (b). Justify your answer in each case.
Step-by-step solution →Show answer
All three in parallel give ; the and in parallel, in series with the , give .
(a) All three resistors are connected in parallel. Then , so . This is possible only in parallel, because a parallel combination is always smaller than the smallest resistor and is smaller than . (b) The and resistors are connected in parallel with each other, and this combination is joined in series with the resistor. For the pair, , so , and in series . - Q33(a) 3 marks
Also in 31/S/1 (Q30(a)), 31/S/3 (Q29(a))
Explain the process of translocation of food and other substances in the phloem of plants.Step-by-step solution →Show answer
Sucrose is loaded into the phloem using ATP, water follows by osmosis, and the resulting pressure moves food from source to sink.
Translocation is the transport of the soluble products of photosynthesis, mainly sucrose, together with amino acids and other substances, through the phloem. It is carried out by the sieve tubes with the help of the companion cells beside them, and unlike transport in the xylem it is an active process that uses energy from ATP. At the source, usually a leaf, sucrose is loaded into the phloem tissue using energy from ATP. This raises the solute concentration inside the sieve tube, so water moves into it by osmosis from the neighbouring xylem. The entry of water builds up a high hydrostatic pressure at the source, and this pressure moves the material in the phloem to the tissues where the pressure is lower, the sinks. At the sink the sucrose is unloaded and used or stored, and the water returns to the xylem. Because the driving force is created within the phloem itself, translocation takes place in both directions, and the plant can send material wherever it is needed; in spring, sugar stored in the root or stem is carried up to the growing buds.ORQ33(b) 3 marksAlso in 31/S/1 (Q30(b)), 31/S/3 (Q29(b))
Differentiate between xylem and phloem on the basis of the following :- (i)Direction of transport of the substances
- (ii)Major driving forces involved in the transport
- (iii)Nature of the substance(s) transported
Step-by-step solution →Show answer
Xylem moves water and minerals upwards passively; phloem moves sucrose and other food both ways using ATP energy.
(i) Direction of transport: in xylem the transport is unidirectional, water and minerals moving only upwards from the roots to the rest of the plant; in phloem it is bidirectional, the material moving from a source to a sink and so travelling both upwards and downwards. (ii) Major driving forces: in xylem the transport is passive and physical, driven mainly by the transpiration pull created by evaporation of water from the leaves, helped by root pressure, and no ATP is used; in phloem the transport is active, energy from ATP being used to load sucrose into the sieve tube, after which water enters by osmosis and the resulting high hydrostatic pressure drives the solution towards the sink. (iii) Nature of the substances transported: xylem carries water and dissolved inorganic minerals absorbed from the soil, while phloem carries the soluble products of photosynthesis, mainly sucrose, together with amino acids and other organic substances.
Questions 34–36 · 5 marks each
- Q34(a) 5 marks
- (i)On adding dilute HCl to a test tube containing sodium carbonate, an effervescence is observed. Explain the observation giving chemical equation for the reaction. How is the gas released tested in a school laboratory ?
- (ii)What happens when excess carbon dioxide passes through lime water ? Write chemical equations to explain your answer.
Step-by-step solution →Show answer
Carbon dioxide is released; it turns lime water milky, and excess carbon dioxide clears it by forming soluble calcium hydrogencarbonate.
(i) Sodium carbonate, a metal carbonate, reacts with dilute hydrochloric acid to form sodium chloride, water and carbon dioxide gas; the bubbles of carbon dioxide escaping from the liquid are the effervescence: . Test: the gas is passed through lime water (calcium hydroxide solution), which turns milky because insoluble white calcium carbonate is formed: . (ii) When carbon dioxide is passed through lime water it first turns milky, as above. On passing excess carbon dioxide the milkiness disappears, because the calcium carbonate reacts with water and more carbon dioxide to form calcium hydrogencarbonate, which is soluble in water: .ORQ34(b) 5 marks- (i)A small amount of copper oxide is taken in a beaker and dilute HCl is added to it slowly. Name the compound formed and state the colour of the solution formed. Write the balanced chemical equation for the reaction that occurs.
- (ii)A compound ‘X’ on heating at 373 K, loses water molecules and becomes ‘Y’. Substance ‘Y’ is used by doctors for supporting fractured bones in the right position. I. Identify ‘X’ and ‘Y’. II. How can ‘X’ be obtained from ‘Y’ ?
Step-by-step solution →Show answer
Copper oxide gives blue-green solution; X is gypsum, Y is Plaster of Paris, and adding water to Y gives X back.
(i) The compound formed is copper(II) chloride, , with water. The copper oxide dissolves and the solution becomes blue-green: . (ii) I. X is gypsum, calcium sulphate dihydrate, ; Y is Plaster of Paris, calcium sulphate hemihydrate, : . II. X is obtained from Y by mixing Plaster of Paris with water; it changes back into gypsum, setting as a hard solid mass: . - Q35(a) 5 marks
- (i)When and where does a rainbow appear in the sky ? List the phenomena of light which occur during the formation of a rainbow in proper sequence. Draw a labelled diagram to show the formation of a rainbow.
- (ii)List two conditions to observe a rainbow in the sky. Why can a rainbow not be seen from the surface of the moon ? Explain.
Step-by-step solution →Show answer
Raindrops refract, internally reflect and refract sunlight to form a rainbow opposite the Sun; the Moon has no atmosphere, so none forms.
(i) A rainbow appears in the sky after a rain shower, when the Sun is shining and tiny water droplets are still present in the air; it is always seen in the direction opposite to the Sun, with the Sun behind the observer. The phenomena in sequence: (1) refraction of sunlight as it enters a raindrop, with dispersion into its colours; (2) internal reflection at the back surface of the drop; (3) refraction again as the light leaves the drop, which disperses the colours further. The labelled diagram shows a raindrop with white sunlight entering it, the points of refraction and dispersion, internal reflection and final refraction marked, and the red and violet rays emerging towards the observer. (ii) Conditions: (1) the Sun must be shining behind the observer and fairly low in the sky; (2) there must be water droplets in the air in front of the observer, opposite the Sun, as after rain or near a waterfall or fountain. A rainbow cannot be seen from the surface of the Moon because the Moon has practically no atmosphere: there are no water droplets above its surface to refract, disperse and internally reflect sunlight.ORQ35(b) 5 marks- (i)What is hypermetropia ? List its two possible causes. Name the type of lens used to correct this defect and state its role in this case.
- (ii)A person suffering from presbyopia needs bifocal lens. If he needs two lenses of power D and D, which one of these two lenses is for the correction of distant vision and what is its focal length ?
Step-by-step solution →Show answer
Hypermetropia is corrected by a convex lens; the concave D lens is for distant vision, with m.
(i) Hypermetropia, or far-sightedness, is the defect of vision in which a person can see distant objects clearly but cannot see nearby objects distinctly; the near point of the eye lies farther than the normal cm, because light from a nearby object is focused at a point behind the retina. Two possible causes: (1) the focal length of the eye lens is too long; (2) the eyeball has become too small. It is corrected with a convex (converging) lens of suitable power. Its role: it supplies the extra converging power the eye lacks, making light from an object at cm seem to come from the person's own near point, so that the eye lens can form the image on the retina. (ii) Since , the D lens is diverging (concave) and the D lens converging (convex). In a common bifocal lens the upper concave portion serves distant vision and the lower convex portion near vision, so the lens for the correction of distant vision is the one of power D. Its focal length is m, that is cm. - Q36(a) 5 marks
Also in 31/S/1 (Q36(a))
- (i)In which form is the information for inheritance of features transmitted from one generation to the next generation ?
- (ii)Differentiate between binary fission in Amoeba and Leishmania.
- (iii)"Fragmentation cannot be a method of reproduction in all multicellular organisms." Justify this statement.
Step-by-step solution →Show answer
Inheritance information is carried as DNA; Amoeba divides in any plane, Leishmania lengthwise; complex bodies cannot fragment because a piece lacks all tissues.
(i) The information for inheritance of features is transmitted from one generation to the next in the form of DNA, that is deoxyribonucleic acid, present in the chromosomes in the nucleus of the cell; its units are the genes, which carry the information for making proteins and so for the body design. (ii) In Amoeba the body has no fixed or definite shape, so binary fission is simple: the cell divides into two daughter cells along any plane, the plane of division not being fixed. In Leishmania the cell has a definite shape with a whip-like structure, a flagellum, at one end, so it has a definite orientation, and binary fission occurs in a definite plane, longitudinally along the length of the cell with respect to that end. (iii) Organisms with a complex body design are not simple collections of cells: their cells are organised into specialised tissues, organs and organ systems placed at definite positions. A fragment of such a body does not contain all the tissues and organs required, and its specialised cells can no longer divide to give rise to every other kind of cell, so it cannot grow into a new individual. Fragmentation works only in simple multicellular organisms of relatively simple body organisation, such as Spirogyra, where any piece of the filament grows into a new plant. Hence fragmentation cannot be a method of reproduction in all multicellular organisms.ORQ36(b) 5 marksAlso in 31/S/1 (Q36(b))
- (i)Define placenta. State the structure and role of placenta in the development of embryo in human beings.
- (ii)List three categories of contraceptives and give one example of each.
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The placenta exchanges glucose, oxygen and wastes between mother and embryo through villi; contraceptives are barrier, chemical and surgical.
(i) The placenta is a special disc-like tissue embedded in the wall of the uterus which connects the developing embryo to the body of the mother and through which substances are exchanged between them. Structure: it contains villi, finger-like projections of tissue on the side of the embryo, and on the side of the mother there are blood spaces surrounding these villi; this provides a very large surface area for exchange, while the two bloodstreams remain separate, and the embryo is joined to it by the umbilical cord. Role: glucose and oxygen pass from the mother to the embryo through the placenta, providing its nutrition and the oxygen for its respiration, and the waste substances generated by the embryo, such as carbon dioxide and urea, are removed into the blood of the mother through it. It also secretes hormones that maintain the pregnancy. (ii) Three categories of contraceptives are: barrier or mechanical methods, example the condom; chemical or hormonal methods, example oral contraceptive pills; and surgical methods, example vasectomy in the male or tubectomy in the female. Intra-uterine contraceptive devices such as the copper T form a further category.
Questions 37–39 · 4 marks each
- Q37 4 marks
Also in 31/S/1 (Q39), 31/S/3 (Q38)
In a domestic circuit, six LED bulbs and a ceiling fan are arranged as per the circuit shown in the figure. The source voltage is 220 volts and the power rating of each device is marked in the circuit diagram. Two fuses and are also provided in the circuit. Based on the circuit diagram, answer the following questions :- (a)State what happens when (i) only key is closed, (ii) and key is also closed.[1]
- (b)Find the current drawn by the bulb L.[1]
- (c)(i)Calculate the resistance of the bulb A. Find the total resistance offered by the circuit to the flow of current when only key is closed.[2]
- (c)(ii)OR : What would happen to the glow of the bulbs in the circuit when and both are closed and the fuse melts suddenly ? Give reason to justify your answer.[2]
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With only the fan and L work; adds A to E; A, , total .
(a)(i) With only closed, only the branch holding fuse , the ceiling fan and bulb L is complete, so the fan runs and bulb L glows, both at their rated 220 V and therefore normally; bulbs A to E do not glow, their branch being open at . The current drawn is A. (ii) When is closed as well, the series string A, B, C, D, E is completed and all five bulbs glow, each receiving V, exactly its rated voltage; the fan and bulb L are unaffected, because the branches are in parallel and each still has the whole 220 V across it, and the total current rises to A. (b) A. (c)(i) . With only closed the only conducting path is the series string of the five bulbs, so the total resistance offered by the circuit is . (c)(ii) The ceiling fan stops and bulb L goes out, because is in series with that branch alone and melting it breaks the branch. The five bulbs A, B, C, D and E continue to glow with exactly the same brightness as before, because they lie in a separate parallel branch that is still connected to the supply through and : the potential difference across that branch is still 220 V, so the current in it is still A and each bulb still has 44 V across it and consumes 10 W. - Q38 4 marks
Also in 31/S/1 (Q37), 31/S/3 (Q39)
All compounds of carbon which contain only carbon and hydrogen are called hydrocarbons. Among these, saturated hydrocarbons are called 'alkanes', unsaturated compounds with one or more double bonds are called 'alkenes' and compounds containing one or more triple bonds are called 'alkynes'.- (a)Identify the following compound and write its name. [1]
- (b)How do saturated and unsaturated carbon compounds differ in terms of the flame produced by them on burning ?[1]
- (c)(i)Which type of hydrocarbons undergo addition reactions ? Show with an example.[2]
- (c)(ii)OR : What are structural isomers ? Draw two structural isomers of butane ().[2]
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It is propyne, an alkyne; saturated compounds burn with a clean blue flame, unsaturated with a sooty yellow flame; alkenes and alkynes undergo addition.
(a) The compound contains a carbon-carbon triple bond, so it is an alkyne; with three carbon atoms (molecular formula ) its name is propyne. (b) A saturated carbon compound burns with a clean blue, non-sooty flame, whereas an unsaturated carbon compound burns with a yellow flame and a great deal of black smoke, because its higher percentage of carbon does not burn completely in a limited supply of air. (c)(i) Unsaturated hydrocarbons, that is the alkenes and the alkynes, undergo addition reactions, because their double or triple bond can open. Example: ethene adds hydrogen over a nickel catalyst to give ethane, . (c)(ii) Structural isomers are compounds having the same molecular formula but different structural formulae, and hence different properties. Butane, , has two structural isomers: n-butane, (a straight chain of four carbon atoms), and iso-butane or 2-methylpropane, (a chain of three carbon atoms with a methyl group on the middle one). - Q39 4 marks
Also in 31/S/1 (Q38), 31/S/3 (Q37)
The process of determining the sex of a newborn is purely genetic. But still many people in some societies believe that only the woman (mother) is responsible for determination of the sex of the child and blame her. In fact, the sex of the child is genetically determined. But there are some animals where sex is not genetically determined.- (a)Define sex chromosomes.[1]
- (b)Mention one example of animals where sex is not genetically determined. How is sex determined in these animals ? Explain.[1]
- (c)(i)Does the genetic combination of the mother play a significant role in determining the sex of newborn ? Explain.[2]
- (c)(ii)OR : How is equal genetic contribution of male and female parents ensured in progeny ?[2]
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Sex chromosomes (XX, XY) decide sex; turtle sex depends on egg temperature; the father's sperm decides a child's sex; each parent gives 23 chromosomes.
(a) Sex chromosomes are the pair of chromosomes that determines the sex of an individual, as opposed to the autosomes, which are alike in both sexes. In human beings they are the twenty-third of the 23 pairs: a female has two X chromosomes (XX) and a male has one X and one Y chromosome (XY). (b) Turtles are one such example (crocodiles and some lizards behave in the same way); snails are another. In turtles the sex is not fixed by the chromosomes but by the environment: the temperature at which the fertilised eggs are incubated during the embryo's development decides whether the young that hatch are males or females. In a snail, an individual can itself change sex. (c)(i) No. The mother is XX, so every egg she produces necessarily carries an X chromosome and she has no other kind of egg to give. The father is XY, so half his sperms carry X and half carry Y. An X-bearing sperm gives an XX zygote, a girl, and a Y-bearing sperm gives an XY zygote, a boy, in equal proportion. The sex of the newborn is therefore decided by the father's sperm, and the mother's genetic combination plays no part in it. (c)(ii) Each parent contributes exactly one chromosome of every pair. A human body cell has 23 pairs, that is 46 chromosomes; during the formation of the germ cells this number is halved, so the egg carries 23 chromosomes and the sperm carries 23; at fertilisation they fuse and the zygote regains 23 + 23 = 46. Since one chromosome of every pair comes from the mother and the other from the father, the progeny inherits one copy of each gene from each parent, which is what makes the genetic contribution of the two parents equal.