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CBSE Class 10 Science 2025 — Paper 31/5/3

80 marks · 3 hours · 39 questions (45 with the OR choices)

33 of its 45 questions also appear in 31/5/1 or 31/5/2; 12 are only in this paper.

Take this paper as a timed mock

Free with an account: the board's time limit, marking at the end, and the answer to every question.

Questions 1–20 · 1 mark each

  1. Q1 1 mark

    Also in 31/5/1 (Q6), 31/5/2 (Q2)

    During electrolytic refining of copper, the anode, the cathode and the electrolyte used respectively are
    1. (a)Impure copper, pure copper, acidified copper sulphate solution
    2. (b)Pure copper, impure copper, sulphuric acid
    3. (c)Pure copper, impure copper, acidified copper sulphate solution
    4. (d)Impure copper, pure copper, distilled water
    Show answer
    (a) Impure copper, pure copper, acidified copper sulphate solution
    Step-by-step solution →
  2. Q2 1 mark

    Also in 31/5/1 (Q7), 31/5/2 (Q1)

    If we make carbon skeleton with four carbon atoms, the two different possible skeletons will be
    (A) C C C C ; C C C C (B) C C C C ; C C C C (C) C C C C ; C C C C (D) C C C C ; C C C C
    1. (a) with a fourth joined below the third carbon; and
    2. (b); and with two further atoms joined to the second carbon
    3. (c); and with a joined below the second carbon and a fourth below that
    4. (d); and with one joined below each of the two carbons
    Show answer
    (b) ; and with two further atoms joined to the second carbon
    Step-by-step solution →
  3. Q3 1 mark

    Also in 31/5/1 (Q5), 31/5/2 (Q4)

    The values of , , and in the following balanced chemical equation are respectively :
    1. (a)1, 1, 2, 1
    2. (b)1, 1, 1, 2
    3. (c)2, 2, 1, 4
    4. (d)2, 2, 4, 1
    Show answer
    (d) 2, 2, 4, 1
    Step-by-step solution →
  4. Q4 1 mark

    Also in 31/5/1 (Q4), 31/5/2 (Q6)

    A metal, 'X', on treatment with sodium hydroxide liberates a gas 'G'. It also liberates the same gas, 'G' on treatment with dilute sulphuric acid. Based on above information, 'X' and 'G' respectively are
    1. (a)Copper and Sulphur dioxide
    2. (b)Zinc and Sulphur dioxide
    3. (c)Zinc and Hydrogen
    4. (d)Copper and Hydrogen
    Show answer
    (c) Zinc and Hydrogen
    Step-by-step solution →
  5. Q5 1 mark
    When a mixture of baking soda and tartaric acid is heated (or mixed in water) a product ‘X’ is formed, which is responsible for making breads and cakes soft and spongy. The product ‘X’ is
    1. (a)Carbon dioxide
    2. (b)Carbon monoxide
    3. (c)Sodium tartrate
    4. (d)Hydrogen
    Show answer
    (a) Carbon dioxide
    Step-by-step solution →
  6. Q6 1 mark

    Also in 31/5/1 (Q2), 31/5/2 (Q7)

    A metal, M, displaces iron from aqueous solution of ferrous sulphate but fails to do so in case of aqueous solution of aluminium sulphate. The metal M is
    1. (a)Magnesium
    2. (b)Copper
    3. (c)Lead
    4. (d)Zinc
    Show answer
    (d) Zinc
    Step-by-step solution →
  7. Q7 1 mark

    Also in 31/5/1 (Q1), 31/5/2 (Q5)

    The main observations while performing the experiment of burning magnesium ribbon in air are :
    1. (i)Magnesium ribbon burns with a dazzling white flame.
    2. (ii)A white powder is formed.
    3. (iii)Magnesium ribbon vapourises.
    4. (iv)Aqueous solution of the white powder turns blue litmus to red.
    1. (a)(i) and (iv)
    2. (b)(ii) and (iii)
    3. (c)(i) and (ii)
    4. (d)(iii) and (iv)
    Show answer
    (c) (i) and (ii)
    Step-by-step solution →
  8. Q8 1 mark

    Also in 31/5/1 (Q12), 31/5/2 (Q13)

    In aerobic respiration, the steps are : breakdown of glucose to pyruvate and its further conversion to carbon dioxide. Both processes respectively occur in –
    1. (a)Vacuole and Cytoplasm
    2. (b)Chloroplast and Mitochondria
    3. (c)Mitochondria and Cytoplasm
    4. (d)Cytoplasm and Mitochondria
    Show answer
    (d) Cytoplasm and Mitochondria
    Step-by-step solution →
  9. Q9 1 mark

    Also in 31/5/1 (Q11), 31/5/2 (Q10)

    The plant hormones promoting rapid cell division in seeds and wilting of leaves respectively are
    1. (a)Auxins and Abscisic acid
    2. (b)Cytokinins and Abscisic acid
    3. (c)Gibberellins and Auxins
    4. (d)Abscisic acid and Gibberellins
    Show answer
    (b) Cytokinins and Abscisic acid
    Step-by-step solution →
  10. Q10 1 mark

    Also in 31/5/1 (Q10), 31/5/2 (Q11)

    The modes of reproduction in Spirogyra and Planaria respectively are
    1. (a)Regeneration and budding
    2. (b)Regeneration and fragmentation
    3. (c)Fragmentation and regeneration
    4. (d)Budding and regeneration
    Show answer
    (c) Fragmentation and regeneration
    Step-by-step solution →
  11. Q11 1 mark

    Also in 31/5/1 (Q9), 31/5/2 (Q8)

    Which among the following is not a neural action controlled by the part of human brain labelled 'X' in the figure above ?
    ‘X’
    1. (a)Salivation
    2. (b)Hunger
    3. (c)Vomiting
    4. (d)Blood Pressure
    Show answer
    (b) Hunger
    Step-by-step solution →
  12. Q12 1 mark

    Also in 31/5/1 (Q8), 31/5/2 (Q9)

    Listed below are the steps of nutrition in Amoeba. Select the correct sequence of these steps :
    1. (i)Diffusion of simple nutrients into cytoplasm
    2. (ii)Food vacuole formation
    3. (iii)Formation of finger like temporary extensions of cell surface
    4. (iv)Complex substances broken to simpler ones
    5. (v)Undigested material thrown out of the cell surface
    1. (a)(iv), (i), (ii), (iii), (v)
    2. (b)(iii), (ii), (iv), (i), (v)
    3. (c)(ii), (i), (iv), (v), (iii)
    4. (d)(iii), (iv), (i), (ii), (v)
    Show answer
    (b) (iii), (ii), (iv), (i), (v)
    Step-by-step solution →
  13. Q13 1 mark

    Also in 31/5/1 (Q16), 31/5/2 (Q15)

    Human activities that are affecting the environment are :
    1. (a)minimising the use of chloroflurocarbons.
    2. (b)excessive use of disposable cups and plates.
    3. (c)maximising the use of reusable utensils for eating food and drinking fluids.
    4. (d)segregating the wastes into biodegradable and non-biodegradable before disposal.
    Show answer
    (b) excessive use of disposable cups and plates.
    Step-by-step solution →
  14. Q14 1 mark

    Also in 31/5/1 (Q15), 31/5/2 (Q16)

    The examples of natural and manmade (artificial) ecosystems are respectively
    1. (a)Forests and ponds
    2. (b)Crop fields and lakes
    3. (c)Lakes and gardens
    4. (d)Crop fields and forests
    Show answer
    (c) Lakes and gardens
    Step-by-step solution →
  15. Q15 1 mark
    Consider the following ray diagram : Here, the angle of incidence and angle of deviation respectively are
    b a c e d f
    1. (a)a and e
    2. (b)b and d
    3. (c)b and e
    4. (d)a and f
    Show answer
    (c) b and e
    Step-by-step solution →
  16. Q16 1 mark

    Also in 31/5/1 (Q13), 31/5/2 (Q12)

    In order to obtain large images of the teeth of patients, the dentist holds the concave mirror in such a manner that the teeth are positioned
    1. (a)at the focus of mirror.
    2. (b)between pole and focus of the mirror.
    3. (c)between focus and centre of curvature of the mirror.
    4. (d)at the centre of curvature of the mirror.
    Show answer
    (b) between pole and focus of the mirror.
    Step-by-step solution →
  17. Q17 1 mark

    Also in 31/5/1 (Q20), 31/5/2 (Q18)

    Question Nos. 17 to 20 consists of two statements – Assertion (A) and Reason (R). Answer these questions selecting the appropriate option from (a), (b), (c) and (d) given below :

    Assertion (A): All organisms can make organic compounds like sugar and starch from inorganic substances using radiant energy of the sun.

    Reason (R): The organisms which can produce food by photosynthesis are called producers.

    1. (a)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
    2. (b)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
    3. (c)Assertion (A) is true, but Reason (R) is false.
    4. (d)Assertion (A) is false, but Reason (R) is true.
    Show answer
    (d) Assertion (A) is false, but Reason (R) is true.
    Step-by-step solution →
  18. Q18 1 mark

    Also in 31/5/1 (Q19), 31/5/2 (Q20)

    Question Nos. 17 to 20 consists of two statements – Assertion (A) and Reason (R). Answer these questions selecting the appropriate option from (a), (b), (c) and (d) given below :

    Assertion (A): The pattern of the magnetic field of a solenoid carrying a current is similar to that of a bar magnet.

    Reason (R): The pattern of the magnetic field around a current carrying conductor is independent of the shape of the conductor.

    1. (a)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
    2. (b)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
    3. (c)Assertion (A) is true, but Reason (R) is false.
    4. (d)Assertion (A) is false, but Reason (R) is true.
    Show answer
    (c) Assertion (A) is true, but Reason (R) is false.
    Step-by-step solution →
  19. Q19 1 mark

    Also in 31/5/1 (Q18), 31/5/2 (Q17)

    Question Nos. 17 to 20 consists of two statements – Assertion (A) and Reason (R). Answer these questions selecting the appropriate option from (a), (b), (c) and (d) given below :

    Assertion (A): The embryo gets nutrition from the mother's blood with the help of a special tissue called placenta.

    Reason (R): Placenta is a disc which is embedded in the uterine wall.

    1. (a)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
    2. (b)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
    3. (c)Assertion (A) is true, but Reason (R) is false.
    4. (d)Assertion (A) is false, but Reason (R) is true.
    Show answer
    (b) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
    Step-by-step solution →
  20. Q20 1 mark

    Also in 31/5/1 (Q17), 31/5/2 (Q19)

    Question Nos. 17 to 20 consists of two statements – Assertion (A) and Reason (R). Answer these questions selecting the appropriate option from (a), (b), (c) and (d) given below :

    Assertion (A): Silver chloride turns grey in sunlight.

    Reason (R): Decomposition of silver chloride into silver and chlorine takes place by sunlight.

    1. (a)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
    2. (b)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
    3. (c)Assertion (A) is true, but Reason (R) is false.
    4. (d)Assertion (A) is false, but Reason (R) is true.
    Show answer
    (a) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
    Step-by-step solution →

Questions 21–26 · 2 marks each

  1. Q21 2 marks
    During an experiment, a student observes that the given mirror is forming an erect and diminished image for all positions of the object placed in front of it. Based on the this information, answer the following questions :
    1. (a)Identify the mirror.
    2. (b)Using new Cartesian sign convention, write the magnitude of the magnification in this case.
    3. (c)What will be the radius of curvature of the mirror if its focal length is 20 cm ?
    Show answer

    It is a convex mirror, with and cm.

    (a) The mirror is a convex mirror: it is the only mirror that gives an erect, diminished image for every position of the object. (b) The magnification is positive, because the image is erect, and less than 1, because the image is diminished: , so its magnitude is less than 1. For example, with cm and cm, cm and . (c) cm cm; with the sign convention cm, since the centre of curvature lies behind a convex mirror.
    Step-by-step solution →
  2. Q22(a) 2 marks
    Determine the maximum and minimum resistance which can be obtained by joining five resistors of each.
    Show answer

    Maximum resistance is (all five in series); minimum is (all five in parallel).

    Maximum resistance: all five resistors in series, . Minimum resistance: all five resistors in parallel, , so .
    Step-by-step solution →
    OR
    Q22(b) 2 marks
    Calculate potential difference across a resistor that produces 100 J of heat every second.
    Show answer

    The potential difference across the resistor is 20 V.

    The heat produced each second is the power: W. From , , so the potential difference across the resistor is V (the current through it is A).
    Step-by-step solution →
  3. Q23 2 marks

    Also in 31/5/1 (Q22), 31/5/2 (Q25)

    Give reasons :
    1. (a)The male reproductive organ responsible for formation of germ cells is located outside the abdominal cavity.
    2. (b)The roles of the glands, present along the path of the vas-deferens, are very significant.
    Show answer

    The testes hang outside the body because sperm formation needs a lower temperature; the glands' secretions carry and nourish the sperms.

    (a) The organ is the testis. Sperms are formed only at a temperature about 2 to 3 C below normal body temperature, and no site inside the abdominal cavity is that cool; the scrotum, hanging outside the cavity, provides the lower temperature, so the testes are located there. (b) The glands along the vas deferens are the seminal vesicles and the prostate gland. Their secretions form the fluid part of the semen: they provide the medium in which the sperms are carried, nourish them, and make their transport easier so that the sperms become motile - which is why their roles are very significant.
    Step-by-step solution →
  4. Q24(a) 2 marks

    Also in 31/5/1 (Q23(a)), 31/5/2 (Q24(a))

    How is lymph formed ? State its important function.
    Show answer

    Plasma and proteins leak from capillaries into tissue spaces as lymph, which carries absorbed fat and drains excess fluid back into the blood.

    Lymph is formed when some plasma, along with some proteins and blood cells, escapes through the pores in the walls of the blood capillaries into the spaces between the cells of a tissue. This fluid, called lymph or tissue fluid, is similar to plasma but is colourless and contains less protein. Its important functions are that it carries digested and absorbed fat from the intestine, through the lacteals of the villi, and that it drains the excess fluid from the extracellular space back into the blood.
    Step-by-step solution →
    OR
    Q24(b) 2 marks

    Also in 31/5/1 (Q23(b)), 31/5/2 (Q24(b))

    1. (a)Identify 'X' in the figure of human nephron shown below. What role does it play in the process of urine formation ?
    2. (b)Why some substances are selectively reabsorbed from the initial filtrate of urine, as it flows along the tabular part of nephron ?
    ‘X’
    Show answer

    X is the Bowman's capsule, which collects the initial filtrate; useful substances are reabsorbed selectively because the body still needs them.

    (a) X is the Bowman's capsule. It is the cup-shaped, double-walled structure at the beginning of the nephron that surrounds the glomerulus. Blood is filtered under pressure in the glomerulus, and the Bowman's capsule collects this initial filtrate - water, glucose, amino acids, salts and urea - and passes it on into the tubular part of the nephron. (b) Filtration separates by size, so the initial filtrate contains useful substances as well as waste. As it flows along the tubular part, glucose, amino acids, most salts and most water are selectively reabsorbed into the blood because the body still needs them and losing them would waste food and water; urea and the excess salts and water are left behind, and what remains is urine.
    Step-by-step solution →
  5. Q25 2 marks
    Study the food web given below :
    1. (a)Identify the food chain(s) in which the eagle receives the highest energy from the producers.
    2. (b)Identify the organism in which a non-biodegradable pesticide will be found in maximum concentration. Name the term used for this phenomenon.
    Eagle Snake Frog Mouse Mongoose Grass Hopper Grass
    Show answer

    (a) Grass to mouse to eagle and grass to mongoose to eagle (shortest chains); (b) the eagle, by biological magnification.

    (a) Grass → Mouse → Eagle and Grass → Mongoose → Eagle. These are the shortest chains in the web, with three trophic levels. Since only about 10% of the energy passes from one level to the next, the eagle receives the most energy through them: about 1% of the energy stored in the grass, against about 0.1% through the four-level chains and about 0.01% through Grass → Grass Hopper → Frog → Snake → Eagle. (b) The eagle. It is the top consumer, at the end of every chain in the web, so a non-biodegradable pesticide reaches its highest concentration in it. The phenomenon is called biological magnification (biomagnification).
    Step-by-step solution →
  6. Q26 2 marks
    A copper wire on burning in flame, gets coated with a black substance. Write the chemical equation of the reaction that takes place. How can this chemical change be reversed ?
    Show answer

    Copper burns to black copper(II) oxide, ; passing hydrogen over the heated wire reverses it.

    The black substance is copper(II) oxide, formed when the hot copper combines with oxygen of the air: The change is reversed by heating the coated wire and passing hydrogen gas over it. The hydrogen removes the oxygen, so the black copper oxide turns back into reddish-brown copper, and water is formed:
    Step-by-step solution →

Questions 27–33 · 3 marks each

  1. Q27 3 marks
    Answer the following questions for a case in which a current carrying conductor is placed in a uniform magnetic field :
    1. (a)List three factors on which the magnitude of the force acting on the conductor depends.
    2. (b)When is the magnitude of force on the conductor maximum ?
    3. (c)Name the rule which helps in determining the direction of force on the conductor and give its one application.
    Show answer

    Force depends on current, field strength and length in the field; it is maximum at right angles to the field; Fleming's left-hand rule.

    (a) The size of the force depends on (i) the current through the conductor, (ii) the strength of the magnetic field and (iii) the length of the conductor that lies in the field; the force increases when any one of them increases. (It also depends on the angle between the conductor and the field, which is part (b).) (b) The force is maximum when the conductor, that is, the direction of the current, is at right angles to the direction of the magnetic field; it is zero when the conductor lies along the field. (c) Fleming's left-hand rule: stretch the thumb, forefinger and middle finger of the left hand so that they are mutually at right angles; if the forefinger points along the magnetic field and the middle finger along the current, the thumb points in the direction of the force (motion) on the conductor. Application: the electric motor works on this principle (so do loudspeakers and measuring instruments such as galvanometers).
    Step-by-step solution →
  2. Q28 3 marks

    Also in 31/5/1 (Q32), 31/5/2 (Q28)

    The resistance of a wire of cm radius is ohms. If the resistivity of the material of the wire is ohm meter, calculate the length of the wire.
    Show answer

    The length of the wire is m, that is 0.005 m.

    m, that is m ( mm or cm).
    Step-by-step solution →
  3. Q29 3 marks

    Also in 31/5/1 (Q31), 31/5/2 (Q29)

    The power of a lens is D. Based on this information, find out
    1. (a)The type of lens and its focal length.
    2. (b)The eye defect for which it may be used as a corrective lens.
    3. (c)The nature and size of the image formed by this lens when an object is placed between F and 2F from the optical centre of this lens.
    Show answer

    Concave lens, m; used for myopia; the image is virtual, erect and diminished, between and .

    (a) m cm. The focal length is negative, so the lens is a concave (diverging) lens of focal length m. (b) It can be used to correct myopia (short-sightedness); a person needing this lens has a far point of about m. (c) The image is virtual, erect and diminished, and is formed between the focus and the optical centre , on the same side of the lens as the object. For example, with m (between and ), m and , so the image is times the size of the object.
    Step-by-step solution →
  4. Q30 3 marks
    Differentiate between self-pollination and cross pollination. Which one of the two is better for the survival of species ? Give reason to justify your answer.
    Show answer

    Cross-pollination is better for survival: it brings more variation, so some individuals can survive changed surroundings, unlike self-pollination, which gives similar offspring.

    Self-pollination and cross-pollination differ as follows. Source of pollen: in self-pollination the pollen reaches the stigma of the same flower (or of another flower on the same plant); in cross-pollination it comes from a flower on another plant of the same species. Agent: self-pollination usually needs no outside agent; cross-pollination needs an agent such as insects, wind or water to carry the pollen. Pollen: self-pollination wastes little pollen; in cross-pollination much of the pollen can be lost on the way, so plants produce it in large amounts. Offspring: in self-pollination all the genes come from one parent plant, so the offspring vary little; cross-pollination combines the genes of two plants, so the offspring show more variation. Cross-pollination is better for the survival of the species. It produces more variation, and when the surroundings change (in temperature, water supply or disease, for example) some of the varied individuals are likely to suit the new conditions and survive, so the species continues; a population of nearly identical individuals could be wiped out by the same change.
    Step-by-step solution →
  5. Q31 3 marks
    List three raw materials required by terrestrial plants for photosynthesis. Explain how nature provides these raw material to the plants.
    Show answer

    Carbon dioxide from air via stomata, water from soil via roots and xylem, and sunlight from the Sun are the raw materials.

    Three raw materials needed by a land plant for photosynthesis are carbon dioxide, water and sunlight; strictly, carbon dioxide and water are the substances used up, and sunlight supplies the energy. (i) Carbon dioxide: the air around the plant contains carbon dioxide, which diffuses into the leaves through the stomata, tiny pores on the surface of the leaf. (ii) Water: rain keeps the soil moist; the roots absorb water from the soil and the xylem carries it up the stem to the leaves. Mineral salts such as nitrates and magnesium, which the plant also needs, are taken up from the soil along with it. (iii) Sunlight: the Sun provides light, which is absorbed by chlorophyll in the chloroplasts of the leaf cells and converted into chemical energy.
    Step-by-step solution →
  6. Q32(a) 3 marks

    Also in 31/5/1 (Q28(a)), 31/5/2 (Q30(a))

    Observe the following diagram showing an experiment to determine the conditions under which a metal ‘M’ corrodes. List your observations in each of the three cases A, B and C with reason, if the metal ‘M’ is generally protected against corrosion by the method of galvanisation.
    MoistAir Metal ‘M’Oil MoistAir Metal ‘M’Oil Dry AirMetal ‘M’ ABC
    Show answer

    M is iron; it rusts in tube A but not in B (oil) or C (dry air), so rusting needs both air and moisture.

    Metal ‘M’ is iron, because galvanisation (coating with zinc) is the method used to protect iron and steel. Tube A: the nail corrodes and a reddish-brown flaky layer of rust forms, because the tube holds moist air, so both water and oxygen reach the metal. Tube B: the nail does not corrode, because the oil covers it completely and keeps both air and moisture away from the metal surface. Tube C: the nail does not corrode, because the granules of drying agent at the bottom absorb the moisture and leave only dry air, so water is absent even though oxygen is present. Conclusion: both air (oxygen) and moisture are necessary together for iron to rust.
    Step-by-step solution →
    OR
    Q32(b) 3 marks

    Also in 31/5/1 (Q28(b)), 31/5/2 (Q30(b))

    1. (a)Show the formation of Aluminium Nitride (AlN) by the transfer of electrons. [ At. no. of Al = 13; At. no. of N = 7 ]
    2. (b)“Ionic compounds are solids and are generally brittle and break into pieces when pressure is applied.” Give reason to justify the statement.
    Show answer

    Al gives three electrons to N to form and , giving AlN; ionic solids are brittle because like charges repel when layers slip.

    (a) has the arrangement and has . Aluminium loses its three outermost electrons and nitrogen gains exactly those three: and . Both ions now have the neon arrangement, and the strong electrostatic attraction between and , combined in the ratio , gives aluminium nitride, . (b) The ions in an ionic compound are packed in a regular three-dimensional lattice in which every ion is surrounded by ions of opposite charge, held by strong electrostatic forces; this makes the compound a hard solid. When pressure is applied, one layer slips over the next and ions of like charge come opposite each other; the strong repulsion between them pushes the layers apart and the crystal breaks along that plane, so ionic solids are brittle.
    Step-by-step solution →
  7. Q33 3 marks

    Also in 31/5/1 (Q27), 31/5/2 (Q31)

    Write chemical formula of washing soda. How is it obtained from baking soda ? List two uses of washing soda.
    Show answer

    Washing soda is , made by heating baking soda and recrystallising the sodium carbonate formed.

    Washing soda is sodium carbonate decahydrate, . It is obtained from baking soda in two stages: (i) baking soda is heated, ; (ii) the sodium carbonate so formed is recrystallised from water, . Two uses: it is used in the glass, soap and paper industries, and it is used for removing the permanent hardness of water (it is also a domestic cleaning agent and a raw material for borax).
    Step-by-step solution →

Questions 34–36 · 5 marks each

  1. Q34(a) 5 marks
    (a) Define the term “Functional group of a carbon compound”. Write the formula of functional group present in
    1. (i)propanol and
    2. (ii)propanone. (b) Name the process of conversion of (i) ethanol to ethene and (ii) ethanol to ethanoic acid. Write the reaction equation stating the conditions required for each of the reactions to occur.
    Show answer

    Functional group gives characteristic properties; propanol has , propanone ; ethanol to ethene is dehydration, ethanol to ethanoic acid is oxidation.

    (a) A functional group is an atom or a group of atoms, such as , or , that replaces hydrogen in a hydrocarbon chain and gives the compound its characteristic chemical properties, whatever the length and nature of the carbon chain. (i) Propanol, : the alcohol group, . (ii) Propanone, : the ketone group, (written in a condensed formula). (b) (i) Ethanol to ethene is dehydration: when ethanol is heated at 443 K with excess concentrated sulphuric acid, the acid removes a molecule of water from each molecule of ethanol. (ii) Ethanol to ethanoic acid is oxidation: ethanol is heated with alkaline potassium permanganate (or acidified potassium dichromate), which adds oxygen to it.
    Step-by-step solution →
    OR
    Q34(b) 5 marks
    1. (a)Name two cyclic hydrocarbons and draw the structure of any one.
    2. (b)Explain the process of micelle formation on adding soap in water.
    Show answer

    Cyclohexane and benzene are cyclic hydrocarbons; soap molecules cluster in water with tails inward and ionic ends outward, forming micelles that trap oily dirt.

    (a) Two cyclic hydrocarbons are cyclohexane, , and benzene, . Structure of cyclohexane: six carbon atoms are joined by single bonds in a closed hexagonal ring, and each carbon atom is also bonded to two hydrogen atoms, so that every carbon forms four bonds (the structure is drawn in the figure; benzene has single and double bonds alternating in its ring and one hydrogen atom on each carbon). (b) A soap molecule, such as sodium stearate, , has two ends with different properties: the ionic carboxylate end is hydrophilic and is attracted to water, while the long hydrocarbon tail is hydrophobic and dissolves in oil but not in water. When soap is added to water, the molecules at the surface line up with their ionic ends in the water and their tails sticking out of it. Inside the water, the molecules gather into clusters in which the hydrocarbon tails point inwards, away from the water, and the ionic ends face outwards into the water. Such a cluster is called a micelle. Oily dirt collects in the hydrocarbon interior of the micelles and is rinsed away with the water, and the micelles stay dispersed because their charged surfaces repel one another.
    Step-by-step solution →
  2. Q35(a) 5 marks

    Also in 31/5/1 (Q35(a)), 31/5/2 (Q36(a))

    (a) Analyse the given situations and interpret the possible reason for each :
    1. (i)Iodine deficiency in diet increases the possibility of a disease of swollen neck in a person.
    2. (ii)Some people in population may have very short heights (dwarfs).
    3. (iii)Thick facial hairs develop in boys at the age of 10-12 years. (b) Explain two reasons which necessitate the need of chemical communication in multicellular organisms.
    Show answer

    Iodine deficiency causes goitre, too little growth hormone causes dwarfism, testosterone brings facial hair; hormones reach every cell and give a steady signal.

    (a) (i) Iodine is needed by the thyroid gland to make the hormone thyroxine. When iodine is missing from the diet the gland cannot make thyroxine, so it enlarges in trying to do so, and the enlarged thyroid shows as a swelling of the neck. The disease is goitre. (ii) Such people secreted too little **growth hormone** from the pituitary gland during childhood, so the growth of the body and of the bones was stunted and the person remained a dwarf. (iii) At about - years the testes begin to secrete the male sex hormone **testosterone**, which brings about the male secondary sexual characters; thick facial hair is one of them. It is a normal change of puberty. (b) 1. An electrical impulse travels only along nerve fibres, so it reaches only the cells that nervous tissue connects to; a hormone released into the blood is carried to **every** cell of the body. 2. A nerve cell must reset itself before it can send another impulse, so nervous signalling cannot be kept up continuously; a hormone gives a slow, steady and long-lasting signal, which is what processes like growth and puberty need.
    Step-by-step solution →
    OR
    Q35(b) 5 marks

    Also in 31/5/1 (Q35(b)), 31/5/2 (Q36(b))

    1. (a)Differentiate between voluntary and involuntary action.
    2. (b)Define reflex action. With the help of a flow diagram, show the correct sequence of path of Nerve impulse from place of its origin.
    Show answer

    Voluntary actions are controlled by the cerebrum, involuntary ones by the mid-brain and medulla; a reflex action is processed by the spinal cord.

    (a) Voluntary action: it is performed knowingly, by the person's own will, and can be started or stopped at will; it is initiated and controlled by the **cerebrum** of the fore-brain; the person is aware of it. Examples: writing, walking, speaking. Involuntary action: it takes place without any conscious will and cannot be started or stopped at will; it is controlled by the **mid-brain** and the **medulla** of the hind-brain; the person is usually unaware of it. Examples: beating of the heart, breathing, peristalsis, salivation. (b) Reflex action is a sudden, rapid and automatic response of the body to a stimulus, in which the message is processed by the spinal cord and the response is made without waiting for the brain to think, for example pulling the hand away on touching a hot object. Flow diagram (path of the nerve impulse): Stimulus Receptor (in the skin) Sensory neuron Spinal cord (relay neuron) Motor neuron Effector (muscle) Response.
    Step-by-step solution →
  3. Q36(a) 5 marks

    Also in 31/5/1 (Q36(a)), 31/5/2 (Q34(a))

    (a) Observe the following diagram and compare
    1. (i)speed of light and
    2. (ii)optical densities of the three media A, B and C. Also give justification for your answer of any one of the two cases in terms of refractive indices of A, B and C. (b) Redraw the path of a ray of light through the three media, if the ray of light starting from medium A falls on the medium B (i) Obliquely and the optical density of medium B is made more than that of A and C. (ii) The ray falls normally from medium A to medium B.
    Medium A Medium B Medium C
    Show answer

    Light is fastest in C ( less than ); A and B are equally dense and C is the rarest.

    In the given diagram the ray goes straight on at the A|B surface and bends away from the normal at the B|C surface. (a) (i) Speed of light: it is the **same** in A and in B, and greatest in C, that is . (ii) Optical density: A and B are equally dense, and C is the rarest of the three, that is density of = density of > density of . Justification in terms of refractive indices: at the A|B surface the angle of refraction equals the angle of incidence, so gives . At the B|C surface the ray bends away from the normal, so the angle of refraction is greater than the angle of incidence and . Hence , and since , . (b) (i) With B made optically denser than A and C, the ray bends **towards** the normal on entering B and **away** from the normal on entering C; because C remains rarer than A, the emergent ray in C makes a larger angle with the normal than the incident ray in A. (ii) At normal incidence the angle of incidence is , so the angle of refraction is at every surface: the ray passes straight through A, B and C without any bending, though its speed changes in each medium.
    Step-by-step solution →
    OR
    Q36(b) 5 marks

    Also in 31/5/1 (Q36(b)), 31/5/2 (Q34(b))

    Analyse the following observation table showing variation of image distance (v) with object distance (u) in case of a convex lens and answer the questions that follow without doing any calculations :
    1. (a)Determine the focal length of the lens. Give reason for your answer.
    2. (b)Find magnification of the image formed in Observation No. 3.
    3. (c)The numerical value of magnifications in cases of observation 1 and 2 is same. List two differences in the images formed in these two cases.
    Variation of image distance (v) with object distance (u) for a convex lens
    Observation NumberObject distance (u) in cmImage distance (v) in cm
    1
    2
    3
    4
    5
    6
    Show answer

    (a) cm; (b) ; (c) observation 1 gives a virtual, erect image, observation 2 a real, inverted one.

    (a) cm. Reason: in observation 4 the image distance and the object distance are numerically equal ( cm each) and lie on opposite sides of the lens. For a convex lens that happens only when the object is placed at , when the image is formed at on the other side, the same size and inverted. Hence cm, so cm. (b) For observation 3, . The image is real, inverted and twice the size of the object. (c) Observation 1 gives and observation 2 gives , so the sizes are the same but the images differ in two ways: (i) The image in observation 1 is **virtual** and **erect**, while the image in observation 2 is **real** and **inverted**. (ii) The image in observation 1 is formed on the **same** side of the lens as the object and cannot be obtained on a screen; the image in observation 2 is formed on the **opposite** side of the lens and can be obtained on a screen.
    Step-by-step solution →

Questions 37–39 · 4 marks each

  1. Q37 4 marks

    Also in 31/5/1 (Q39), 31/5/2 (Q37)

    In order to obtain magnetic field lines around a bar magnet, a student performed an experiment using a magnetic compass and a bar magnet. The magnet was placed on a sheet of white paper fixed on a drawing board. Using magnetic needle he obtained on the paper a pattern of magnetic field lines (as shown below) around the bar magnet.
    S N
    1. (a)By convention, the field lines emerge from north pole and merge at south pole. Why ? Give reason.[1]
    2. (b)State the relationship between strength of the magnetic field and the degree of closeness of the field lines.[1]
    3. (c)(i)(i) No two field lines can ever intersect each other. Give reason. (ii) The magnetic field in a given region is uniform. Draw a diagram to represent it.[2]
    4. (c)(ii)OR : Draw the pattern of the magnetic field lines through and around a current carrying solenoid. What does the pattern of field lines inside the solenoid represent ?[2]
    Show answer

    Lines emerge from N and merge at S; closer lines mean a stronger field; lines never cross; the field inside a solenoid is uniform.

    (a) The direction of a magnetic field line at a point is the direction in which the north pole of a small compass needle placed there comes to rest, that is, the direction of the force on a free north pole. Outside the magnet such a free north pole is repelled by the north pole of the magnet and attracted by its south pole, so it moves away from the north pole and towards the south pole. The line it traces is therefore drawn emerging from the north pole and merging at the south pole. (Inside the magnet the direction is from south to north, so every field line is a closed curve.) (b) The strength of the magnetic field is directly related to the closeness of the field lines: the more closely the lines are spaced, the stronger the field, and the farther apart they are, the weaker the field. The degree of closeness - the number of field lines crossing unit area held at right angles to them - represents the relative strength of the field. (c)(i) (i) If two field lines intersected, the magnetic field at the point of intersection would have two directions at the same time, so a compass needle placed there would have to point in two directions at once. That is impossible, so no two field lines can ever intersect. (ii) A uniform magnetic field is represented by straight field lines that are parallel to one another, equally spaced, and all pointing in the same direction (see the diagram). (c)(ii) Outside a current-carrying solenoid the field lines emerge from one end, which behaves as a north pole, loop round and enter the other end, which behaves as a south pole, exactly as they do for a bar magnet; inside the solenoid they run straight along the axis, parallel to one another and equally spaced (see the diagram). That pattern inside represents a uniform magnetic field: the magnetic field is the same, in magnitude and in direction, at all points inside the solenoid.
    Step-by-step solution →
  2. Q38 4 marks

    Also in 31/5/1 (Q37), 31/5/2 (Q39)

    The combining capacity of various elements depends on the number of valence electrons. Also the reactivity of elements is explained as their tendency to attain a completely filled outer shell, that is, to attain a noble gas configuration. This may be either through gain of electrons or loss of electrons or sharing of electrons.
    1. (a)An element A has atomic number 16, how will it attain its nearest noble gas configuration ?[1]
    2. (b)Write the number of (i) single and (ii) double covalent bonds in a molecule of butene ().[1]
    3. (c)(i)Explain the formation of a molecule of ammonia (), using electron dot structure. (Atomic number of nitrogen is 7)[2]
    4. (c)(ii)OR : Why does carbon share its valence electrons with other atoms of carbon or with atoms of other elements ?[2]
    Show answer

    Element A gains two electrons (); butene has 10 single and 1 double bond; ammonia has three shared pairs and a lone pair.

    (a) Element A has the electronic configuration , so its outermost shell is two electrons short of the argon configuration . It attains its nearest noble gas configuration by gaining two electrons, becoming the negative ion . (b) Butene, , has single covalent bonds (eight and two ) and double covalent bond (one ). (c)(i) Nitrogen has five valence electrons and needs three more, while each hydrogen has one and needs one more. Nitrogen shares one electron with each of three hydrogen atoms, giving three shared pairs, that is three single covalent bonds, and the two electrons of nitrogen that are left over stay as a lone pair. Nitrogen then counts eight electrons and each hydrogen two. (c)(ii) Carbon has four valence electrons. It cannot gain four, because a nucleus of six protons could not hold ten electrons, and it cannot lose four, because removing four electrons from one atom needs an enormous amount of energy. It therefore shares its four valence electrons with other atoms of carbon or with atoms of other elements, forming four covalent bonds and attaining a stable octet.
    Step-by-step solution →
  3. Q39 4 marks

    Also in 31/5/1 (Q38), 31/5/2 (Q38)

    In human beings, there are 23 pairs of chromosomes. Out of these 23 pairs of chromosomes (i.e. 46 chromosomes), 22 pairs of chromosomes are called autosomes and one pair of chromosomes. i.e. two chromosomes are called sex chromosomes. The sex chromosomes are of two types — ‘X’ chromosomes and ‘Y’ chromosomes. The sex of a child (i.e. progeny), is decided at the time of fertilisation. In other words, at the time of zygote formation the sex chromosomes inherited from the parents of a child decide whether the new born will be a boy or a girl.
    1. (a)What are chromosomes ?[1]
    2. (b)Why is the pair of sex chromosomes in human males called mismatched pair ?[1]
    3. (c)(i)Show with the help of a flow chart that the statistical probability of getting a boy or a girl is 50 : 50.[2]
    4. (c)(ii)OR : Mention two examples of animals where sex is not determined genetically like human beings. Describe in brief the method of sex determination in these animals.[2]
    Show answer

    Chromosomes carry genes; the male XY pair is mismatched; boys and girls are ; turtles and snails show non-genetic sex.

    (a) Chromosomes are thread-like structures present in the nucleus of a cell, made of DNA and protein, which carry the genes and are passed on from the parents to the offspring; a human cell carries pairs of them. (b) In a human male the sex-chromosome pair is one X and one Y. The Y is much smaller than the X and carries a different set of genes, so the two members of the pair are unlike each other, unlike the matched XX pair of a female - which is why it is called a mismatched pair. (c)(i) The mother is , so every egg is ; the father is , so half his sperms are and half are . An egg fertilised by an X-bearing sperm gives , a girl, and by a Y-bearing sperm gives , a boy. The two kinds of sperm are equally frequent, so , that is . (c)(ii) Turtles and snails. In turtles the sex of the young is decided by the temperature at which the fertilised eggs are incubated - warmer nests give females and cooler nests give males - and not by the chromosomes inherited. In snails an individual can change its sex during its life, functioning as a male at one time and as a female at another, so sex is not fixed genetically at all.
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