CBSE Class 10 Science 2025 — Paper 31/5/1
80 marks · 3 hours · 39 questions (45 with the OR choices)
33 of its 45 questions also appear in 31/5/2 or 31/5/3; 12 are only in this paper.
Take this paper as a timed mock
Free with an account: the board's time limit, marking at the end, and the answer to every question.
Questions 1–20 · 1 mark each
- Q1 1 mark
Also in 31/5/2 (Q5), 31/5/3 (Q7)
The main observations while performing the experiment of burning magnesium ribbon in air are :- (i)Magnesium ribbon burns with a dazzling white flame.
- (ii)A white powder is formed.
- (iii)Magnesium ribbon vapourises.
- (iv)Aqueous solution of the white powder turns blue litmus to red.
- (a)(i) and (iv)
- (b)(ii) and (iii)
- (c)(i) and (ii)
- (d)(iii) and (iv)
Step-by-step solution →Show answer
(c) (i) and (ii) - Q2 1 mark
Also in 31/5/2 (Q7), 31/5/3 (Q6)
A metal, M, displaces iron from aqueous solution of ferrous sulphate but fails to do so in case of aqueous solution of aluminium sulphate. The metal M is- (a)Magnesium
- (b)Copper
- (c)Lead
- (d)Zinc
Step-by-step solution →Show answer
(d) Zinc - Q3 1 markA common feature observed in the crystals of washing soda, copper sulphate, gypsum and ferrous sulphate is that all
- (a)exhibit basic nature
- (b)exhibit acidic nature
- (c)have fixed number of molecules of water of crystallisation in one formula unit of these salts.
- (d)are coloured
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(c) have fixed number of molecules of water of crystallisation in one formula unit of these salts. - Q4 1 mark
Also in 31/5/2 (Q6), 31/5/3 (Q4)
A metal, 'X', on treatment with sodium hydroxide liberates a gas 'G'. It also liberates the same gas, 'G' on treatment with dilute sulphuric acid. Based on above information, 'X' and 'G' respectively are- (a)Copper and Sulphur dioxide
- (b)Zinc and Sulphur dioxide
- (c)Zinc and Hydrogen
- (d)Copper and Hydrogen
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(c) Zinc and Hydrogen - Q5 1 mark
Also in 31/5/2 (Q4), 31/5/3 (Q3)
The values of , , and in the following balanced chemical equation are respectively :- (a)1, 1, 2, 1
- (b)1, 1, 1, 2
- (c)2, 2, 1, 4
- (d)2, 2, 4, 1
Step-by-step solution →Show answer
(d) 2, 2, 4, 1 - Q6 1 mark
Also in 31/5/2 (Q2), 31/5/3 (Q1)
During electrolytic refining of copper, the anode, the cathode and the electrolyte used respectively are- (a)Impure copper, pure copper, acidified copper sulphate solution
- (b)Pure copper, impure copper, sulphuric acid
- (c)Pure copper, impure copper, acidified copper sulphate solution
- (d)Impure copper, pure copper, distilled water
Step-by-step solution →Show answer
(a) Impure copper, pure copper, acidified copper sulphate solution - Q7 1 mark
Also in 31/5/2 (Q1), 31/5/3 (Q2)
If we make carbon skeleton with four carbon atoms, the two different possible skeletons will be- (a) with a fourth joined below the third carbon; and
- (b); and with two further atoms joined to the second carbon
- (c); and with a joined below the second carbon and a fourth below that
- (d); and with one joined below each of the two carbons
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(b) ; and with two further atoms joined to the second carbon - Q8 1 mark
Also in 31/5/2 (Q9), 31/5/3 (Q12)
Listed below are the steps of nutrition in Amoeba. Select the correct sequence of these steps :- (i)Diffusion of simple nutrients into cytoplasm
- (ii)Food vacuole formation
- (iii)Formation of finger like temporary extensions of cell surface
- (iv)Complex substances broken to simpler ones
- (v)Undigested material thrown out of the cell surface
- (a)(iv), (i), (ii), (iii), (v)
- (b)(iii), (ii), (iv), (i), (v)
- (c)(ii), (i), (iv), (v), (iii)
- (d)(iii), (iv), (i), (ii), (v)
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(b) (iii), (ii), (iv), (i), (v) - Q9 1 mark
Also in 31/5/2 (Q8), 31/5/3 (Q11)
Which among the following is not a neural action controlled by the part of human brain labelled 'X' in the figure above ?- (a)Salivation
- (b)Hunger
- (c)Vomiting
- (d)Blood Pressure
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(b) Hunger - Q10 1 mark
Also in 31/5/2 (Q11), 31/5/3 (Q10)
The modes of reproduction in Spirogyra and Planaria respectively are- (a)Regeneration and budding
- (b)Regeneration and fragmentation
- (c)Fragmentation and regeneration
- (d)Budding and regeneration
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(c) Fragmentation and regeneration - Q11 1 mark
Also in 31/5/2 (Q10), 31/5/3 (Q9)
The plant hormones promoting rapid cell division in seeds and wilting of leaves respectively are- (a)Auxins and Abscisic acid
- (b)Cytokinins and Abscisic acid
- (c)Gibberellins and Auxins
- (d)Abscisic acid and Gibberellins
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(b) Cytokinins and Abscisic acid - Q12 1 mark
Also in 31/5/2 (Q13), 31/5/3 (Q8)
In aerobic respiration, the steps are : breakdown of glucose to pyruvate and its further conversion to carbon dioxide. Both processes respectively occur in –- (a)Vacuole and Cytoplasm
- (b)Chloroplast and Mitochondria
- (c)Mitochondria and Cytoplasm
- (d)Cytoplasm and Mitochondria
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(d) Cytoplasm and Mitochondria - Q13 1 mark
Also in 31/5/2 (Q12), 31/5/3 (Q16)
In order to obtain large images of the teeth of patients, the dentist holds the concave mirror in such a manner that the teeth are positioned- (a)at the focus of mirror.
- (b)between pole and focus of the mirror.
- (c)between focus and centre of curvature of the mirror.
- (d)at the centre of curvature of the mirror.
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(b) between pole and focus of the mirror. - Q14 1 markThe possible way to restore clear vision of those people whose eyeball has elongated is the use of suitable
- (a)bifocal lens
- (b)concave lens
- (c)converging lens
- (d)convex lens
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(b) concave lens - Q15 1 mark
Also in 31/5/2 (Q16), 31/5/3 (Q14)
The examples of natural and manmade (artificial) ecosystems are respectively- (a)Forests and ponds
- (b)Crop fields and lakes
- (c)Lakes and gardens
- (d)Crop fields and forests
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(c) Lakes and gardens - Q16 1 mark
Also in 31/5/2 (Q15), 31/5/3 (Q13)
Human activities that are affecting the environment are :- (a)minimising the use of chloroflurocarbons.
- (b)excessive use of disposable cups and plates.
- (c)maximising the use of reusable utensils for eating food and drinking fluids.
- (d)segregating the wastes into biodegradable and non-biodegradable before disposal.
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(b) excessive use of disposable cups and plates. - Q17 1 mark
Also in 31/5/2 (Q19), 31/5/3 (Q20)
Question Nos. 17 to 20 consists of two statements – Assertion (A) and Reason (R). Answer these questions selecting the appropriate option from (a), (b), (c) and (d) given below :Assertion (A): Silver chloride turns grey in sunlight.
Reason (R): Decomposition of silver chloride into silver and chlorine takes place by sunlight.
- (a)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- (b)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- (c)Assertion (A) is true, but Reason (R) is false.
- (d)Assertion (A) is false, but Reason (R) is true.
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(a) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A). - Q18 1 mark
Also in 31/5/2 (Q17), 31/5/3 (Q19)
Question Nos. 17 to 20 consists of two statements – Assertion (A) and Reason (R). Answer these questions selecting the appropriate option from (a), (b), (c) and (d) given below :Assertion (A): The embryo gets nutrition from the mother's blood with the help of a special tissue called placenta.
Reason (R): Placenta is a disc which is embedded in the uterine wall.
- (a)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- (b)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- (c)Assertion (A) is true, but Reason (R) is false.
- (d)Assertion (A) is false, but Reason (R) is true.
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(b) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A). - Q19 1 mark
Also in 31/5/2 (Q20), 31/5/3 (Q18)
Question Nos. 17 to 20 consists of two statements – Assertion (A) and Reason (R). Answer these questions selecting the appropriate option from (a), (b), (c) and (d) given below :Assertion (A): The pattern of the magnetic field of a solenoid carrying a current is similar to that of a bar magnet.
Reason (R): The pattern of the magnetic field around a current carrying conductor is independent of the shape of the conductor.
- (a)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- (b)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- (c)Assertion (A) is true, but Reason (R) is false.
- (d)Assertion (A) is false, but Reason (R) is true.
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(c) Assertion (A) is true, but Reason (R) is false. - Q20 1 mark
Also in 31/5/2 (Q18), 31/5/3 (Q17)
Question Nos. 17 to 20 consists of two statements – Assertion (A) and Reason (R). Answer these questions selecting the appropriate option from (a), (b), (c) and (d) given below :Assertion (A): All organisms can make organic compounds like sugar and starch from inorganic substances using radiant energy of the sun.
Reason (R): The organisms which can produce food by photosynthesis are called producers.
- (a)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
- (b)Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- (c)Assertion (A) is true, but Reason (R) is false.
- (d)Assertion (A) is false, but Reason (R) is true.
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(d) Assertion (A) is false, but Reason (R) is true.
Questions 21–26 · 2 marks each
- Q21 2 marksA crystalline substance of green colour 'X' emits gases of characteristic odour when heated over a flame. It first loses water and changes colour. On further heating, it decomposes and produces a solid compound Y.
- (a)Identify 'X' and 'Y'.
- (b)State the change in colour observed when 'X' is heated.
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X is ferrous sulphate crystals and Y is ferric oxide; the colour changes from green to white and then reddish brown.
(a) is ferrous sulphate crystals, (green vitriol), and is ferric oxide, . (b) The green crystals first turn white (dirty white) as the water of crystallisation is driven off, and on further heating the residue turns reddish brown. - Q22 2 marks
Also in 31/5/2 (Q25), 31/5/3 (Q23)
Give reasons :- (a)The male reproductive organ responsible for formation of germ cells is located outside the abdominal cavity.
- (b)The roles of the glands, present along the path of the vas-deferens, are very significant.
Step-by-step solution →Show answer
The testes hang outside the body because sperm formation needs a lower temperature; the glands' secretions carry and nourish the sperms.
(a) The organ is the testis. Sperms are formed only at a temperature about 2 to 3 C below normal body temperature, and no site inside the abdominal cavity is that cool; the scrotum, hanging outside the cavity, provides the lower temperature, so the testes are located there. (b) The glands along the vas deferens are the seminal vesicles and the prostate gland. Their secretions form the fluid part of the semen: they provide the medium in which the sperms are carried, nourish them, and make their transport easier so that the sperms become motile - which is why their roles are very significant. - Q23(a) 2 marks
Also in 31/5/2 (Q24(a)), 31/5/3 (Q24(a))
How is lymph formed ? State its important function.Step-by-step solution →Show answer
Plasma and proteins leak from capillaries into tissue spaces as lymph, which carries absorbed fat and drains excess fluid back into the blood.
Lymph is formed when some plasma, along with some proteins and blood cells, escapes through the pores in the walls of the blood capillaries into the spaces between the cells of a tissue. This fluid, called lymph or tissue fluid, is similar to plasma but is colourless and contains less protein. Its important functions are that it carries digested and absorbed fat from the intestine, through the lacteals of the villi, and that it drains the excess fluid from the extracellular space back into the blood.ORQ23(b) 2 marksAlso in 31/5/2 (Q24(b)), 31/5/3 (Q24(b))
- (a)Identify 'X' in the figure of human nephron shown below. What role does it play in the process of urine formation ?
- (b)Why some substances are selectively reabsorbed from the initial filtrate of urine, as it flows along the tabular part of nephron ?
Step-by-step solution →Show answer
X is the Bowman's capsule, which collects the initial filtrate; useful substances are reabsorbed selectively because the body still needs them.
(a) X is the Bowman's capsule. It is the cup-shaped, double-walled structure at the beginning of the nephron that surrounds the glomerulus. Blood is filtered under pressure in the glomerulus, and the Bowman's capsule collects this initial filtrate - water, glucose, amino acids, salts and urea - and passes it on into the tubular part of the nephron. (b) Filtration separates by size, so the initial filtrate contains useful substances as well as waste. As it flows along the tubular part, glucose, amino acids, most salts and most water are selectively reabsorbed into the blood because the body still needs them and losing them would waste food and water; urea and the excess salts and water are left behind, and what remains is urine. - Q24 2 marksThe values of absolute refractive indices of kerosene and water are 1.44 and 1.33 respectively. Compare the two media on the basis of their
- (a)optical density
- (b)mass density
- (c)relative speed of propagation of light. What do you infer on the basis of above comparisons ?
Step-by-step solution →Show answer
Kerosene is optically denser but less dense in mass than water, and light is slower in it, so the two densities are independent.
(a) Optical density: kerosene has the larger refractive index (), so kerosene is optically denser than water. (b) Mass density: water is denser in mass, about kg/m against about kg/m for kerosene, which is why kerosene floats on water. (c) Speed of light: from , m/s and m/s, so light travels faster in water than in kerosene. Inference: optical density and mass density are independent properties - kerosene is optically denser yet has the smaller mass density - because optical density is decided by how much the medium slows light down and not by its mass per unit volume. - Q25(a) 2 marks(A) State two applications of Joule's heating in domestic electric circuit. (B) Establish the relationship between the commercial unit of electric energy and the SI unit of electric energy.Step-by-step solution →
Show answer
Joule heating is used in heating appliances and the electric fuse; .
(A) Two applications of Joule's heating in a domestic circuit: (i) heating appliances such as the electric iron, room heater, toaster or geyser, in which a coil of high-resistance wire converts electrical energy into heat; and (ii) the electric fuse, a wire of low melting point that melts and breaks the circuit when the current becomes excessive. (The filament of an incandescent lamp is another example.) (B) The commercial unit is the kilowatt hour and the SI unit is the joule. .ORQ25(b) 2 marks(A) State two applications of Joule's heating in domestic electric circuit. (B) Determine the total resistance of the parallel combination of three resistances of , and .Step-by-step solution →Show answer
Joule heating is used in heating appliances and in the fuse; the parallel combination has .
(A) Two applications of Joule's heating in a domestic circuit: (i) heating appliances such as the electric iron, room heater, toaster or geyser, whose element is a coil of high-resistance wire; and (ii) the electric fuse, a wire of low melting point that melts and breaks the circuit when the current becomes excessive. (The filament of an incandescent lamp is another example.) (B) , so (to two decimal places). - Q26 2 marks
- (a)Why are the organisms of first trophic level important in any food chain ?
- (b)Justify the following statement : 'The flow of energy in an ecosystem is unidirectional.'
Step-by-step solution →Show answer
Producers capture the Sun's energy for all other organisms; energy enters once, moves one way and is lost as heat: unidirectional.
(a) The first trophic level is occupied by the producers, the green plants and other autotrophs. They are the only organisms in a food chain that can capture the sun's radiant energy and convert it by photosynthesis into the chemical energy of food, so energy enters the living world only through them. Every other organism depends on them directly or indirectly for food and energy, and without them no food chain could exist. (b) Energy enters an ecosystem only as sunlight and only at the producers; it then passes from producers to herbivores and from herbivores to carnivores, and never in the reverse direction. At each transfer only about of the energy reaches the next trophic level, while about is used up in life processes and lost to the surroundings as heat, which no organism can capture and turn back into food. Since energy enters at one point, travels one way and is steadily lost as unusable heat, its flow in an ecosystem is unidirectional.
Questions 27–33 · 3 marks each
- Q27 3 marks
Also in 31/5/2 (Q31), 31/5/3 (Q33)
Write chemical formula of washing soda. How is it obtained from baking soda ? List two uses of washing soda.Step-by-step solution →Show answer
Washing soda is , made by heating baking soda and recrystallising the sodium carbonate formed.
Washing soda is sodium carbonate decahydrate, . It is obtained from baking soda in two stages: (i) baking soda is heated, ; (ii) the sodium carbonate so formed is recrystallised from water, . Two uses: it is used in the glass, soap and paper industries, and it is used for removing the permanent hardness of water (it is also a domestic cleaning agent and a raw material for borax). - Q28(a) 3 marks
Also in 31/5/2 (Q30(a)), 31/5/3 (Q32(a))
Observe the following diagram showing an experiment to determine the conditions under which a metal ‘M’ corrodes. List your observations in each of the three cases A, B and C with reason, if the metal ‘M’ is generally protected against corrosion by the method of galvanisation.Step-by-step solution →Show answer
M is iron; it rusts in tube A but not in B (oil) or C (dry air), so rusting needs both air and moisture.
Metal ‘M’ is iron, because galvanisation (coating with zinc) is the method used to protect iron and steel. Tube A: the nail corrodes and a reddish-brown flaky layer of rust forms, because the tube holds moist air, so both water and oxygen reach the metal. Tube B: the nail does not corrode, because the oil covers it completely and keeps both air and moisture away from the metal surface. Tube C: the nail does not corrode, because the granules of drying agent at the bottom absorb the moisture and leave only dry air, so water is absent even though oxygen is present. Conclusion: both air (oxygen) and moisture are necessary together for iron to rust.ORQ28(b) 3 marksAlso in 31/5/2 (Q30(b)), 31/5/3 (Q32(b))
- (a)Show the formation of Aluminium Nitride (AlN) by the transfer of electrons. [ At. no. of Al = 13; At. no. of N = 7 ]
- (b)“Ionic compounds are solids and are generally brittle and break into pieces when pressure is applied.” Give reason to justify the statement.
Step-by-step solution →Show answer
Al gives three electrons to N to form and , giving AlN; ionic solids are brittle because like charges repel when layers slip.
(a) has the arrangement and has . Aluminium loses its three outermost electrons and nitrogen gains exactly those three: and . Both ions now have the neon arrangement, and the strong electrostatic attraction between and , combined in the ratio , gives aluminium nitride, . (b) The ions in an ionic compound are packed in a regular three-dimensional lattice in which every ion is surrounded by ions of opposite charge, held by strong electrostatic forces; this makes the compound a hard solid. When pressure is applied, one layer slips over the next and ions of like charge come opposite each other; the strong repulsion between them pushes the layers apart and the crystal breaks along that plane, so ionic solids are brittle. - Q29 3 marks
- (a)Write the name and one function of respiratory pigment found in human beings.
- (b)Why do lungs always contain a residual volume of air ?
- (c)Why is ATP known as energy currency of the living beings ?
Step-by-step solution →Show answer
Haemoglobin carries oxygen; residual air keeps alveoli open and allows time for exchange; ATP stores and releases energy for all cell activities.
(a) The respiratory pigment is haemoglobin, present in the red blood cells. It has a very high affinity for oxygen: it binds oxygen in the alveoli of the lungs and carries it to all the tissues of the body, where it releases it. (b) We never breathe out completely, so a residual volume of air always stays in the lungs. It keeps the alveoli inflated so that they do not collapse, and it keeps air in contact with the exchange surface, giving sufficient time for oxygen to be absorbed and carbon dioxide to be released even between two breaths. (c) The energy released in cellular respiration is used to make ATP from ADP and inorganic phosphate, and whenever a cell needs energy — for muscle contraction, protein synthesis or nerve impulse conduction — the terminal phosphate bond of ATP is broken and that energy is released. Since energy is stored and spent in this one molecule throughout the body, ATP is called the energy currency of living beings. - Q30 3 marks
- (a)Define fertilisation.
- (b)What happens to Zygote, Ovule, Ovary and Stamens after fertilisation in a flowering plant ?
Step-by-step solution →Show answer
Fertilisation is the fusion of male gamete and egg; afterwards the zygote becomes the embryo, ovule the seed and ovary the fruit.
(a) Fertilisation is the fusion of the male gamete, brought by the pollen tube, with the female gamete (egg cell) present in the ovule, to form a single cell called the zygote. (b) Zygote: it divides repeatedly and develops into the embryo of the seed. Ovule: its wall hardens into the seed coat and the whole ovule develops into the seed. Ovary: it grows and ripens to form the fruit, which encloses the seeds. Stamens: their work is over once pollen has been supplied, so they wither and fall off, as do the petals, sepals, style and stigma. - Q31 3 marks
Also in 31/5/2 (Q29), 31/5/3 (Q29)
The power of a lens is D. Based on this information, find out- (a)The type of lens and its focal length.
- (b)The eye defect for which it may be used as a corrective lens.
- (c)The nature and size of the image formed by this lens when an object is placed between F and 2F from the optical centre of this lens.
Step-by-step solution →Show answer
Concave lens, m; used for myopia; the image is virtual, erect and diminished, between and .
(a) m cm. The focal length is negative, so the lens is a concave (diverging) lens of focal length m. (b) It can be used to correct myopia (short-sightedness); a person needing this lens has a far point of about m. (c) The image is virtual, erect and diminished, and is formed between the focus and the optical centre , on the same side of the lens as the object. For example, with m (between and ), m and , so the image is times the size of the object. - Q32 3 marks
Also in 31/5/2 (Q28), 31/5/3 (Q28)
The resistance of a wire of cm radius is ohms. If the resistivity of the material of the wire is ohm meter, calculate the length of the wire.Step-by-step solution →Show answer
The length of the wire is m, that is 0.005 m.
m, that is m ( mm or cm). - Q33 3 marks
- (a)“The third wire of earth connection is very important in domestic electric appliances.” Justify this statement.
- (b)List two precautions to be taken to avoid the overloading of domestic electric circuits.
Step-by-step solution →Show answer
The earth wire carries leaking current safely to the ground, preventing shock; avoid overloading by not crowding sockets or circuits.
(a) The earth wire, insulated in green, joins the metal body of an appliance through the third pin of the plug to a metal plate buried deep in the earth, giving a conducting path of very low resistance to the earth. If the live wire's insulation fails and the live wire touches the metal body, the body would be at a high potential and would give a severe shock to anyone touching it. With the earth connection the body stays at the potential of the earth and the leakage current flows through the earth wire, whose resistance is a fraction of an ohm, rather than through the person, whose resistance is thousands of ohms; the large current also blows the fuse and disconnects the appliance. This is why the third wire is essential in metal-bodied, high-power appliances such as an electric iron, a toaster or a refrigerator. (b) Two precautions against overloading: (i) Do not connect too many appliances to a single socket, that is, avoid running several appliances from one socket through a multi-plug or an extension board. (ii) Do not switch on too many high-power appliances, such as a heater, a geyser and an air conditioner, on the same circuit at the same time; use separate circuits, each with a fuse or MCB of the proper rating and wires of adequate thickness.
Questions 34–36 · 5 marks each
- Q34(a) 5 marks
- (a)What is meant by the term homologous series of carbon compounds ? Write molecular formula of any two consecutive members of homologous series of ketones.
- (b)Write chemical equation of the reactions of ethanoic acid with (i) Sodium hydroxide and (ii) Ethanol (in the presence of an acid); giving the name of the products in each case. (c) Draw the structure of the molecule of benzene.
Step-by-step solution →Show answer
A homologous series has one functional group and members differing by ; ethanoic acid gives sodium ethanoate with NaOH and ethyl ethanoate with ethanol.
(a) A homologous series is a family of carbon compounds having the **same** functional group, in which each member differs from the next by a unit (a mass difference of u). All members fit one general formula, they have similar chemical properties, and their physical properties change gradually along the series. Two consecutive members of the ketone series (): propanone and butanone . (b) (i) ; the products are sodium ethanoate (sodium acetate) and water. (ii) ; the products are ethyl ethanoate (an ester) and water. (c) Benzene, , is a ring of six carbon atoms with alternate single and double bonds and one hydrogen atom on each carbon, as drawn in the figure.ORQ34(b) 5 marks(a) Write the molecular formula of ethyne and draw its electron dot structure. (b) Write chemical equation to show the reaction of ethanol with- (i)Sodium metal
- (ii)Ethanoic acid (in the presence of an acid)
- (iii)Acidified potassium dichromate Write the name of the product formed in each case.
Step-by-step solution →Show answer
Ethyne is with a triple bond; ethanol gives sodium ethoxide with sodium, an ester with ethanoic acid and ethanoic acid with dichromate.
(a) Ethyne is . In its electron dot structure each carbon shares one pair of electrons with its hydrogen atom and **three** pairs with the other carbon, written (that is ), so each carbon has eight electrons around it. (b) (i) ; the products are sodium ethoxide and hydrogen gas. (ii) ; the product is ethyl ethanoate, an ester (with water). (iii) ; the product is ethanoic acid. - Q35(a) 5 marks
Also in 31/5/2 (Q36(a)), 31/5/3 (Q35(a))
(a) Analyse the given situations and interpret the possible reason for each :- (i)Iodine deficiency in diet increases the possibility of a disease of swollen neck in a person.
- (ii)Some people in population may have very short heights (dwarfs).
- (iii)Thick facial hairs develop in boys at the age of 10-12 years. (b) Explain two reasons which necessitate the need of chemical communication in multicellular organisms.
Step-by-step solution →Show answer
Iodine deficiency causes goitre, too little growth hormone causes dwarfism, testosterone brings facial hair; hormones reach every cell and give a steady signal.
(a) (i) Iodine is needed by the thyroid gland to make the hormone thyroxine. When iodine is missing from the diet the gland cannot make thyroxine, so it enlarges in trying to do so, and the enlarged thyroid shows as a swelling of the neck. The disease is goitre. (ii) Such people secreted too little **growth hormone** from the pituitary gland during childhood, so the growth of the body and of the bones was stunted and the person remained a dwarf. (iii) At about - years the testes begin to secrete the male sex hormone **testosterone**, which brings about the male secondary sexual characters; thick facial hair is one of them. It is a normal change of puberty. (b) 1. An electrical impulse travels only along nerve fibres, so it reaches only the cells that nervous tissue connects to; a hormone released into the blood is carried to **every** cell of the body. 2. A nerve cell must reset itself before it can send another impulse, so nervous signalling cannot be kept up continuously; a hormone gives a slow, steady and long-lasting signal, which is what processes like growth and puberty need.ORQ35(b) 5 marksAlso in 31/5/2 (Q36(b)), 31/5/3 (Q35(b))
- (a)Differentiate between voluntary and involuntary action.
- (b)Define reflex action. With the help of a flow diagram, show the correct sequence of path of Nerve impulse from place of its origin.
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Voluntary actions are controlled by the cerebrum, involuntary ones by the mid-brain and medulla; a reflex action is processed by the spinal cord.
(a) Voluntary action: it is performed knowingly, by the person's own will, and can be started or stopped at will; it is initiated and controlled by the **cerebrum** of the fore-brain; the person is aware of it. Examples: writing, walking, speaking. Involuntary action: it takes place without any conscious will and cannot be started or stopped at will; it is controlled by the **mid-brain** and the **medulla** of the hind-brain; the person is usually unaware of it. Examples: beating of the heart, breathing, peristalsis, salivation. (b) Reflex action is a sudden, rapid and automatic response of the body to a stimulus, in which the message is processed by the spinal cord and the response is made without waiting for the brain to think, for example pulling the hand away on touching a hot object. Flow diagram (path of the nerve impulse): Stimulus Receptor (in the skin) Sensory neuron Spinal cord (relay neuron) Motor neuron Effector (muscle) Response. - Q36(a) 5 marks
Also in 31/5/2 (Q34(a)), 31/5/3 (Q36(a))
(a) Observe the following diagram and compare- (i)speed of light and
- (ii)optical densities of the three media A, B and C. Also give justification for your answer of any one of the two cases in terms of refractive indices of A, B and C. (b) Redraw the path of a ray of light through the three media, if the ray of light starting from medium A falls on the medium B (i) Obliquely and the optical density of medium B is made more than that of A and C. (ii) The ray falls normally from medium A to medium B.
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Light is fastest in C ( less than ); A and B are equally dense and C is the rarest.
In the given diagram the ray goes straight on at the A|B surface and bends away from the normal at the B|C surface. (a) (i) Speed of light: it is the **same** in A and in B, and greatest in C, that is . (ii) Optical density: A and B are equally dense, and C is the rarest of the three, that is density of = density of > density of . Justification in terms of refractive indices: at the A|B surface the angle of refraction equals the angle of incidence, so gives . At the B|C surface the ray bends away from the normal, so the angle of refraction is greater than the angle of incidence and . Hence , and since , . (b) (i) With B made optically denser than A and C, the ray bends **towards** the normal on entering B and **away** from the normal on entering C; because C remains rarer than A, the emergent ray in C makes a larger angle with the normal than the incident ray in A. (ii) At normal incidence the angle of incidence is , so the angle of refraction is at every surface: the ray passes straight through A, B and C without any bending, though its speed changes in each medium.ORQ36(b) 5 marksAlso in 31/5/2 (Q34(b)), 31/5/3 (Q36(b))
Analyse the following observation table showing variation of image distance (v) with object distance (u) in case of a convex lens and answer the questions that follow without doing any calculations :- (a)Determine the focal length of the lens. Give reason for your answer.
- (b)Find magnification of the image formed in Observation No. 3.
- (c)The numerical value of magnifications in cases of observation 1 and 2 is same. List two differences in the images formed in these two cases.
Variation of image distance (v) with object distance (u) for a convex lens Observation Number Object distance (u) in cm Image distance (v) in cm 1 2 3 4 5 6 Step-by-step solution →Show answer
(a) cm; (b) ; (c) observation 1 gives a virtual, erect image, observation 2 a real, inverted one.
(a) cm. Reason: in observation 4 the image distance and the object distance are numerically equal ( cm each) and lie on opposite sides of the lens. For a convex lens that happens only when the object is placed at , when the image is formed at on the other side, the same size and inverted. Hence cm, so cm. (b) For observation 3, . The image is real, inverted and twice the size of the object. (c) Observation 1 gives and observation 2 gives , so the sizes are the same but the images differ in two ways: (i) The image in observation 1 is **virtual** and **erect**, while the image in observation 2 is **real** and **inverted**. (ii) The image in observation 1 is formed on the **same** side of the lens as the object and cannot be obtained on a screen; the image in observation 2 is formed on the **opposite** side of the lens and can be obtained on a screen.
Questions 37–39 · 4 marks each
- Q37 4 marks
Also in 31/5/2 (Q39), 31/5/3 (Q38)
The combining capacity of various elements depends on the number of valence electrons. Also the reactivity of elements is explained as their tendency to attain a completely filled outer shell, that is, to attain a noble gas configuration. This may be either through gain of electrons or loss of electrons or sharing of electrons.- (a)An element A has atomic number 16, how will it attain its nearest noble gas configuration ?[1]
- (b)Write the number of (i) single and (ii) double covalent bonds in a molecule of butene ().[1]
- (c)(i)Explain the formation of a molecule of ammonia (), using electron dot structure. (Atomic number of nitrogen is 7)[2]
- (c)(ii)OR : Why does carbon share its valence electrons with other atoms of carbon or with atoms of other elements ?[2]
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Element A gains two electrons (); butene has 10 single and 1 double bond; ammonia has three shared pairs and a lone pair.
(a) Element A has the electronic configuration , so its outermost shell is two electrons short of the argon configuration . It attains its nearest noble gas configuration by gaining two electrons, becoming the negative ion . (b) Butene, , has single covalent bonds (eight and two ) and double covalent bond (one ). (c)(i) Nitrogen has five valence electrons and needs three more, while each hydrogen has one and needs one more. Nitrogen shares one electron with each of three hydrogen atoms, giving three shared pairs, that is three single covalent bonds, and the two electrons of nitrogen that are left over stay as a lone pair. Nitrogen then counts eight electrons and each hydrogen two. (c)(ii) Carbon has four valence electrons. It cannot gain four, because a nucleus of six protons could not hold ten electrons, and it cannot lose four, because removing four electrons from one atom needs an enormous amount of energy. It therefore shares its four valence electrons with other atoms of carbon or with atoms of other elements, forming four covalent bonds and attaining a stable octet. - Q38 4 marks
Also in 31/5/2 (Q38), 31/5/3 (Q39)
In human beings, there are 23 pairs of chromosomes. Out of these 23 pairs of chromosomes (i.e. 46 chromosomes), 22 pairs of chromosomes are called autosomes and one pair of chromosomes. i.e. two chromosomes are called sex chromosomes. The sex chromosomes are of two types — ‘X’ chromosomes and ‘Y’ chromosomes. The sex of a child (i.e. progeny), is decided at the time of fertilisation. In other words, at the time of zygote formation the sex chromosomes inherited from the parents of a child decide whether the new born will be a boy or a girl.- (a)What are chromosomes ?[1]
- (b)Why is the pair of sex chromosomes in human males called mismatched pair ?[1]
- (c)(i)Show with the help of a flow chart that the statistical probability of getting a boy or a girl is 50 : 50.[2]
- (c)(ii)OR : Mention two examples of animals where sex is not determined genetically like human beings. Describe in brief the method of sex determination in these animals.[2]
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Chromosomes carry genes; the male XY pair is mismatched; boys and girls are ; turtles and snails show non-genetic sex.
(a) Chromosomes are thread-like structures present in the nucleus of a cell, made of DNA and protein, which carry the genes and are passed on from the parents to the offspring; a human cell carries pairs of them. (b) In a human male the sex-chromosome pair is one X and one Y. The Y is much smaller than the X and carries a different set of genes, so the two members of the pair are unlike each other, unlike the matched XX pair of a female - which is why it is called a mismatched pair. (c)(i) The mother is , so every egg is ; the father is , so half his sperms are and half are . An egg fertilised by an X-bearing sperm gives , a girl, and by a Y-bearing sperm gives , a boy. The two kinds of sperm are equally frequent, so , that is . (c)(ii) Turtles and snails. In turtles the sex of the young is decided by the temperature at which the fertilised eggs are incubated - warmer nests give females and cooler nests give males - and not by the chromosomes inherited. In snails an individual can change its sex during its life, functioning as a male at one time and as a female at another, so sex is not fixed genetically at all. - Q39 4 marks
Also in 31/5/2 (Q37), 31/5/3 (Q37)
In order to obtain magnetic field lines around a bar magnet, a student performed an experiment using a magnetic compass and a bar magnet. The magnet was placed on a sheet of white paper fixed on a drawing board. Using magnetic needle he obtained on the paper a pattern of magnetic field lines (as shown below) around the bar magnet.- (a)By convention, the field lines emerge from north pole and merge at south pole. Why ? Give reason.[1]
- (b)State the relationship between strength of the magnetic field and the degree of closeness of the field lines.[1]
- (c)(i)(i) No two field lines can ever intersect each other. Give reason. (ii) The magnetic field in a given region is uniform. Draw a diagram to represent it.[2]
- (c)(ii)OR : Draw the pattern of the magnetic field lines through and around a current carrying solenoid. What does the pattern of field lines inside the solenoid represent ?[2]
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Lines emerge from N and merge at S; closer lines mean a stronger field; lines never cross; the field inside a solenoid is uniform.
(a) The direction of a magnetic field line at a point is the direction in which the north pole of a small compass needle placed there comes to rest, that is, the direction of the force on a free north pole. Outside the magnet such a free north pole is repelled by the north pole of the magnet and attracted by its south pole, so it moves away from the north pole and towards the south pole. The line it traces is therefore drawn emerging from the north pole and merging at the south pole. (Inside the magnet the direction is from south to north, so every field line is a closed curve.) (b) The strength of the magnetic field is directly related to the closeness of the field lines: the more closely the lines are spaced, the stronger the field, and the farther apart they are, the weaker the field. The degree of closeness - the number of field lines crossing unit area held at right angles to them - represents the relative strength of the field. (c)(i) (i) If two field lines intersected, the magnetic field at the point of intersection would have two directions at the same time, so a compass needle placed there would have to point in two directions at once. That is impossible, so no two field lines can ever intersect. (ii) A uniform magnetic field is represented by straight field lines that are parallel to one another, equally spaced, and all pointing in the same direction (see the diagram). (c)(ii) Outside a current-carrying solenoid the field lines emerge from one end, which behaves as a north pole, loop round and enter the other end, which behaves as a south pole, exactly as they do for a bar magnet; inside the solenoid they run straight along the axis, parallel to one another and equally spaced (see the diagram). That pattern inside represents a uniform magnetic field: the magnetic field is the same, in magnitude and in direction, at all points inside the solenoid.