To construct a triangle similar to a given △ABC with its sides 7/3 of the corresponding sides of △ABC, draw a…

To construct a triangle similar to a given $△ABC$ with its sides $\frac{7}{3}$ of the corresponding sides of $△ABC$, draw a ray $BX$ making acute angle with $BC$ and $X$ lies on the opposite side of $A$ with respect to $BC$. The points $B_1,B_2,\dots ,B_7$ are located at equal distances on $BX$, $B_3$ is joined to $C$ and then a line segment $B_6{C}^{\prime }$ is drawn parallel to $B_{3}C$ where $C^{\prime }$ lies on $BC$ produced. Finally, line segment $A^{\prime }{C}^{\prime }$ is drawn parallel to $CA$. Is this construction correct? Justify.