To construct a triangle similar to a given △ABC with its sides 3/7 of the corresponding sides of △ABC, first…

To construct a triangle similar to a given $△ABC$ with its sides $\frac{3}{7}$ of the corresponding sides of $△ABC$, first draw a ray BX such that $\angle CBX$ is an acute angle and X lies on the opposite side of A with respect to BC. Then locate points $B_1,B_2,B_3,\dots$ on BX at equal distances and next step is to join