CBSE Class 10 Maths (Basic) 2025 · Paper 430/S/1 · Question 28

Introduction to Trigonometry 3 marks Medium

Prove that :

\frac{sin θ - 2 sin ^{3} θ}{2 cos ^{3} θ - cos θ} = tan θ

Answer

LHS

= \frac{sin θ ( 1 - 2 sin ^{2} θ )}{cos θ ( 2 cos ^{2} θ - 1 )} = \frac{sin θ ( 2 cos ^{2} θ - 1 )}{cos θ ( 2 cos ^{2} θ - 1 )} = \frac{sin θ}{cos θ} = tan θ =

RHS. Hence proved.

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