CBSE Class 10 Science 2017 · Paper 31/2/1 · Question 36

Light - Reflection and Refraction 2 marks Medium

Trace the path of a ray of light incident at an angle of

4 5^{\circ}

on a rectangular glass slab. Write the measure of the angle of refraction, the angle of emergence and the lateral displacement suffered by the ray as it passes through the slab.

Answer

$r \approx 2 8^{\circ}$ , $e = 4 5^{\circ}$ and the lateral displacement is about $0.33 t$ (1.6 cm for a 5 cm thick slab).

Angle of refraction

r \approx 2 8^{\circ}

(for glass of refractive index about 1.5). Angle of emergence

e = 4 5^{\circ}

, equal to the angle of incidence: the emergent ray is parallel to the incident ray. Lateral displacement, the perpendicular distance between the emergent ray and the incident ray produced: about a third of the slab's thickness,

d = \frac{t sin ( i - r )}{cos r} \approx 0.33 t

— about 1.6 cm for a slab 5 cm thick.

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CBSE Class 10 Science 2017 · Paper 31/2/1 · Question 36

Answer

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