CBSE Class 10 Maths (Standard) 2020 · Paper 30/1/1 · Question 22(a)

Triangles 2 marks Medium

In Fig. 2,

D E ∥ A C

and

D C ∥ A P

. Prove that

\frac{B E}{E C} = \frac{B C}{C P}

DE parallel to AC and DC parallel to AP, with base points B, E, C, P

Answer

Since both ratios equal

\frac{B D}{D A}

, we conclude

\frac{B E}{E C} = \frac{B C}{C P}

. Hence proved.

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