CBSE Class 10 Maths (Standard) 2020 · Paper 30/5/1 · Question 21

Triangles 2 marks Medium

In the given Figure-5,

D E ∥ A C

and

D F ∥ A E

. Prove that

\frac{B F}{F E} = \frac{B E}{E C}

Figure-5: Triangle ABC with DE parallel to AC and DF parallel to AE.

Answer

Proved:

\frac{B F}{F E} = \frac{B D}{D A} = \frac{B E}{E C}

, hence

\frac{B F}{F E} = \frac{B E}{E C}

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