Class 10 Maths · Triangles · NCERT Exercise 6.3 · Question 8
E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that .
Answer
Proved: , by the AA similarity criterion.
Step-by-step solution
Every step of how it is worked out, free, with no account needed.
From the book
NCERT Class 10 Maths Exercise 6.3 — all 16 questions with answers →
More questions from Triangles
Class 10 Maths — every question with an expert-verified, step-by-step solution.
- Q1 Fill in the blanks using the correct word given in brackets: (i) All…
- Q2 Give two different examples of pair of: (i) similar figures (ii…
- Q3 State whether the following quadrilaterals are similar or not:
- Q1 In Fig. 6.17, (i) and (ii), DE || BC. Find EC in (i) and AD in (ii…
- Q2 E and F are points on the sides PQ and PR respectively of a triangle…
- Q3 In Fig. 6.18, if LM ∥ CB and LN ∥ CD, prove that AM/(AB)=AN/(AD).
- Q4 In Fig. 6.19, DE ∥ AC and DF ∥ AE. Prove that BF/(FE) = BE/(EC).
- Q5 In Fig. 6.20, DE ∥ OQ and DF ∥ OR. Show that EF ∥ QR.
- Q6 In Fig. 6.21, A, B and C are points on OP, OQ and OR respectively…
- Q7 Using Theorem 6.1, prove that a line drawn through the mid-point of…
- Q8 Using Theorem 6.2, prove that the line joining the mid-points of an…
- Q9 ABCD is a trapezium in which AB ∥ DC and its diagonals intersect ea…
All 424 questions on Triangles → Browse all Maths chapters →