CBSE Class 10 Maths (Standard) 2020 · Paper 30/4/1 · Question 22(b)

Triangles 2 marks Medium

In Figure-5,

△ P QR

is right-angled at

P

M

is a point on

QR

such that

P M

is perpendicular to

QR

. Show that

P Q^{2} = QM \times QR

Right triangle PQR with altitude PM to the hypotenuse QR

Answer

Since

△ QM P \sim △ QP R

\frac{QM}{QP} = \frac{QP}{QR}

, so

P Q^{2} = QM \times QR

. Hence proved.

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