CBSE Class 10 Maths (Standard) 2020 · Paper 30/3/1 · Question 6(b)

Arithmetic Progressions 1 mark Easy

The number of terms of an AP

5, 9, 13, \dots, 185

(a) $31$
(b) $51$
(c) $41$
(d) $40$

Answer

CBSE awarded this mark to every candidate. The AP

5, 9, 13, \dots, 185

has

n = \frac{185 - 5}{4} + 1 = 46

terms, and

46

is not among the printed options — the misprint is in the original 2020 question paper, which the portal reproduces faithfully. The official marking scheme for set 30/3/1 records: "1 mark should be given to each candidate."

🔒 Step-by-step solution

From the board paper

CBSE Class 10 Maths (Standard) 2020 · Paper 30/3/1, Question 6(b) — all 40 questions with answers →

More questions from Arithmetic Progressions

Class 10 Maths — every question with an expert-verified, step-by-step solution.

Q1 In which of the following situations does the list of numbers involv…
Q2 Write the first four terms of the AP when the first term a and t…
Q3 For the following APs, write the first term and the common diff…
Q4 Which of the following are APs? If they form an AP, find the commo…
Q1 Fill in the blanks in the following table, given that a is the fir…
Q2 Choose the correct choice in the following and justify: (i) 30th te…
Q3 In the following APs, find the missing terms in the boxes: (i) 2,…
Q4 Which term of the AP: 3, 8, 13, 18, …, is 78?
Q5 Find the number of terms in each of the following APs: (i) 7, 13,…
Q6 Check whether -150 is a term of the AP: 11, 8, 5, 2, …
Q7 Find the 31st term of an AP whose 11th term is 38 and the 16t…
Q8 An AP consists of 50 terms of which 3rd term is 12 and the last…

All 441 questions on Arithmetic Progressions → Browse all Maths chapters →