Class 10 Maths · Introduction to Trigonometry · NCERT Exercise 8.3 · Question 3

Introduction to Trigonometry Medium

Choose the correct option. Justify your choice.

(i) $9 sec^{2} A - 9 tan^{2} A =$ (A) 1 (B) 9 (C) 8 (D) 0.
(ii) $(1 + tan θ + sec θ) (1 + cot θ - csc θ) =$ (A) 0 (B) 1 (C) 2 (D) -1.
(iii) $(sec A + tan A) (1 - sin A) =$ (A) $sec A$ (B) $sin A$ (C) $csc A$ (D) $cos A$ .
(iv) $\frac{1 + tan ^{2} A}{1 + cot ^{2} A} =$ (A) $sec^{2} A$ (B) -1 (C) $cot^{2} A$ (D) $tan^{2} A$ .

Answer

(i) (B)

9

; (ii) (C)

2

; (iii) (D)

cos A

; (iv) (D)

tan^{2} A

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