CBSE Class 10 Science 2018 · Paper 31/1/C · Question 5

Position: $v=-40$ cm, so the image is formed $40$ cm in front of the mirror, at the centre of curvature $C$ (the same place as the object). Nature: real and inverted, and of the same size as the object ($m=-\frac{v}{u}=-1$). Ray diagram: a ray from the top of the object parallel to the axis is reflected through $F$, and a ray through $F$ is reflected parallel to the axis; they meet below $C$, where the inverted image forms (see the figure).