\sin(45^\circ + \theta) - \cos(45^\circ - \theta) is equal to — Quest4Learn

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Mathematics Introduction to Trigonometry

sin (4 5^{\circ} + θ) - cos (4 5^{\circ} - θ)

is equal to

(a) $2 cos θ$
(b) $0$
(c) $2 sin θ$
(d) $1$

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