CBSE Class 10 Maths (Standard) 2023 · Paper 30/5/1 · Question 28(a)

Triangles 3 marks Hard

In the given figure,

C D

is the perpendicular bisector of

A B

E F

is perpendicular to

C D

A E

intersects

C D

G

. Prove that

\frac{C F}{C D} = \frac{F G}{D G}

CD perpendicular bisector of AB, EF perpendicular to CD, AE meeting CD at G.

Answer

\frac{C F}{C D} = \frac{F G}{D G}

(proved)

🔒 Step-by-step solution

Class 10 Maths — every question with an expert-verified, step-by-step solution.