Class 10 Maths · Triangles · NCERT Exercise 6.4 · Question 15

Triangles Hard

O is the point of intersection of the diagonals AC and BD of a trapezium ABCD with

A B ∥ D C

. Through O, a line segment PQ is drawn parallel to AB meeting AD in P and BC in Q. Prove that

P O = QO

Answer

Proved:

\frac{P O}{D C} = \frac{A O}{A C} = \frac{B O}{B D} = \frac{O Q}{D C}

, therefore

P O = QO

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