CBSE Class 10 Science 2020 · Paper 31/2/1 · Question 25(a)
- (a)How is the method of extraction of metals high up in the reactivity series different from that for metals in the middle ? Why cannot the same process be applied for them ? Name and explain the process of extraction of sodium.
- (b)Draw a labelled diagram of electrolytic refining of copper.
Answer
Carbon reduces oxides of middle metals but not highly reactive ones, which are electrolysed; sodium forms at the cathode, and copper is refined electrolytically.
(a) Metals in the middle of the reactivity series (zinc, iron, lead, copper) usually occur as sulphides or carbonates; the ore is first converted into the oxide, by roasting a sulphide or calcining a carbonate, and the oxide is then reduced to the metal by heating it with carbon. Metals high up in the series (potassium, sodium, calcium, magnesium, aluminium) cannot be obtained this way: they are extracted by electrolytic reduction of their molten chlorides or oxides. The carbon process cannot be applied to them because these metals have a greater affinity for oxygen than carbon has, so carbon cannot reduce their oxides.
Extraction of sodium is by electrolytic reduction: electricity is passed through molten sodium chloride; sodium metal is deposited at the cathode and chlorine gas is liberated at the anode.
At the cathode:
At the anode:
(b) Labelled diagram (see the figure): a tank of acidified copper sulphate solution as the electrolyte, a block of impure copper as the anode (+), a thin strip of pure copper as the cathode (−), and the anode mud of insoluble impurities below the anode; copper dissolves from the anode and pure copper is deposited on the cathode.
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