CBSE Class 10 Science 2019 · Paper 31/2/1 · Question 13(b)

Position: $v=+36$ cm, so the image is formed $36$ cm from the lens on the side opposite to the object (beyond $2F_2$). Nature: real and inverted ($v$ is positive and $m=\frac{v}{u}=\frac{36}{-18}=-2$), and magnified. Size: $h^{\prime }=m\times h=-2\times 10=-20$ cm, so the image is $20$ cm tall, twice the height of the object, and inverted.