CBSE Class 10 Science 2022 · Paper 31/4/2 · Question 3

Carbon and its Compounds 2 marks Medium

Consider the following molecular formulae of carbon compounds :

(i) $CH_{3} COOH$
(ii) $CH_{3} OH$
(iii) $C_{2} H_{6}$
(iv) $C_{3} H_{4}$
(v) $C_{4} H_{8}$ (a) Which one of these compounds belongs to homologous series of alcohols ? (b) Identify the compound having triple bond between carbon – carbon atoms. (c) Write the molecular formula of the first member of the homologous series to which $CH_{3} COOH$ belongs. (d) Write the general formula of the series to which the compound $C_{4} H_{8}$ belongs.

Answer

Methanol is the alcohol; $C_{3} H_{4}$ has the triple bond; the first acid is $HCOOH$ ; the alkene formula is $C_{n} H_{2 n}$ .

(a) Methanol,

CH_{3} OH

, belongs to the homologous series of alcohols. (b)

C_{3} H_{4}

(propyne,

H - C \equiv C - CH_{3}

) has a triple bond between two carbon atoms. (c) The first member of the carboxylic acid series is methanoic acid,

HCOOH

(molecular formula

CH_{2} O_{2}

). (d)

C_{4} H_{8}

belongs to the alkene series, whose general formula is

C_{n} H_{2 n}

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