CBSE Class 10 Science 2017 · Paper 31/1/C · Question 12

(i) The compound formed is ethyl ethanoate, ${\text{CH}}_3{\text{COOC}}_2{\text{H}}_5$. It has a sweet (fruity) smell and belongs to the class of compounds called esters. (ii) ${\text{CH}}_3\text{COOH}+{\text{C}}_2{\text{H}}_5\text{OH}\stackrel{{\text{conc. H}}_2{\text{SO}}_4}{\to }{\text{CH}}_3{\text{COOC}}_2{\text{H}}_5+{\text{H}}_2\text{O}$ (ethanoic acid + ethanol gives ethyl ethanoate + water; the reaction is esterification). Conc. ${\text{H}}_2{\text{SO}}_4$ acts as the acid catalyst; it also takes up the water formed, which helps the reaction go forward. (iii) The ester is used in making perfumes and as a flavouring agent.