CBSE Class 10 Maths (Standard) 2025 · Paper 30/5/1 · Question 32(b)

Quadratic Equations 5 marks Medium

Find the value(s) of

p

for which the quadratic equation given as

(p + 4) x^{2} - (p + 1) x + 1 = 0

has real and equal roots. Also, find the roots of the equation(s) so obtained.

Answer

The values are

p = 5

and

p = - 3

. For

p = 5

the equation is

9 x^{2} - 6 x + 1 = 0

with equal roots

\frac{1}{3}, \frac{1}{3}

; for

p = - 3

it is

x^{2} + 2 x + 1 = 0

with equal roots

- 1, - 1

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