CBSE Class 10 Science 2024 — Paper 31/2/3
80 marks · 3 hours · 39 questions (45 with the OR choices)
29 of its 45 questions also appear in 31/2/1, 31/2/2 and other papers; 16 are only in this paper.
Take this paper as a timed mock
Free with an account: the board's time limit, marking at the end, and the answer to every question.
Questions 1–20 · 1 mark each
- Q1 1 markAn iron nail is placed in a solution of copper sulphate. The nail is taken out after 15 minutes. The nail will be found to be covered with :
- (a)blue deposit
- (b)brown deposit
- (c)grey deposit
- (d)green deposit
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(b) brown deposit - Q2 1 mark
Also in 31/2/1 (Q5)
Consider the following cases :- (a)
- (b)
- (c)
- (d) The cases in which new products will form are –
- (a)(a) and (b)
- (b)(b) and (c)
- (c)(c) and (d)
- (d)(b) and (d)
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(d) (b) and (d) - Q3 1 markWhich of the following reactions is an endothermic reaction ?
- (a)Burning of coal
- (b)Decomposition of vegetable matter into compost
- (c)Process of respiration
- (d)Decomposition of calcium carbonate to form quick lime and carbon dioxide.
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(d) Decomposition of calcium carbonate to form quick lime and carbon dioxide. - Q4 1 mark
Also in 31/2/1 (Q4), 31/2/2 (Q4)
The oxide which can react with as well as to give corresponding salt and water is- (a)
- (b)
- (c)
- (d)
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(b) - Q5 1 mark
Also in 31/2/1 (Q2)
Juice of tamarind turns blue litmus to red. It is because of the presence of an acid called :- (a)methanoic acid
- (b)acetic acid
- (c)tartaric acid
- (d)oxalic acid
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(c) tartaric acid - Q6 1 mark
Also in 31/2/1 (Q7), 31/2/2 (Q1)
Consider the following statements about homologous series of carbon compounds :- (a)All succeeding members differ by unit.
- (b)Melting point and boiling point increases with increasing molecular mass.
- (c)The difference in molecular masses between two successive members is 16 u.
- (d) and are NOT the successive members of alkyne series. The correct statements are –
- (a)(a) and (b)
- (b)(b) and (c)
- (c)(a) and (c)
- (d)(c) and (d)
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(a) (a) and (b) - Q7 1 mark
Also in 31/2/1 (Q6)
Identify the correct statement about the following reaction :- (a) is oxidising agent and is reducing agent.
- (b) is reduced to sulphur.
- (c) is oxidising agent and is reducing agent.
- (d) is oxidised to sulphur.
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(c) is oxidising agent and is reducing agent. - Q8 1 markIn the given diagram the leaf shown belongs to which plant ?
- (a)Hibiscus
- (b)Money plant
- (c)Mustard
- (d)Bryophyllum
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(d) Bryophyllum - Q9 1 mark
Also in 31/2/1 (Q9), 31/2/2 (Q9)
Select out of the following a gland which does NOT occur as a pair in the human body :- (a)Pituitary
- (b)Ovary
- (c)Testis
- (d)Adrenal
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(a) Pituitary - Q10 1 mark
Also in 31/2/1 (Q10), 31/2/2 (Q8)
In human respiratory system, when a person breathes in, the position of ribs and diaphragm will be :- (a)lifted ribs and curve/dome shaped diaphragm.
- (b)lifted ribs and flattened diaphragm.
- (c)relaxed ribs and flattened diaphragm.
- (d)relaxed ribs and curve/dome shaped diaphragm.
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(b) lifted ribs and flattened diaphragm. - Q11 1 mark
Also in 31/2/1 (Q8), 31/2/2 (Q10)
Which of the following statement(s) is (are) true about human heart ?- (a)Right atrium receives oxygenated blood from lungs through pulmonary artery.
- (b)Left atrium transfers oxygenated blood to left ventricle which sends it to various parts of the body.
- (c)Right atrium receives deoxygenated blood through vena cava from upper and lower body.
- (d)Left atrium transfers oxygenated blood to aorta which sends it to different parts of the body.
- (a)(a)
- (b)(a) and (d)
- (c)(b) and (c)
- (d)(b) and (d)
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(c) (b) and (c) - Q12 1 mark
Also in 2025 · 31(B)/S (Q12), 31/2/1 (Q12), 31/2/2 (Q12)
A cross made between two pea plants produces 50% tall and 50% short pea plants. The gene combination of the parental pea plants must be- (a)Tt and Tt
- (b)TT and Tt
- (c)Tt and tt
- (d)TT and tt
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(c) Tt and tt - Q13 1 mark
Also in 31/2/1 (Q15)
Study the I-V graph for three resistors of resistances , and and select the correct statement from the following :- (a)
- (b)
- (c)
- (d)
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(c) - Q14 1 mark
Also in 31/2/1 (Q14)
The maximum resistance of a network of five identical resistors of each can be –- (a)
- (b)
- (c)
- (d)
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(a) - Q15 1 markThe speed of light in vacuum is m/s. If the speed of light in a medium is m/s, the absolute refractive index of the medium is :
- (a)
- (b)
- (c)
- (d)
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(c) - Q16 1 markStudy the following statements :
- (a)A fuse in a circuit prevents damage to the circuit due to overloading.
- (b)Total resistance in a circuit increases due to overloading.
- (c)During short circuiting the current in the circuit abruptly increases.
- (d)In order that each appliance has same current, they are connected in parallel to each other. The correct statements are
- (a)(a) and (b)
- (b)(b) and (d)
- (c)(a) and (c)
- (d)(a), (c) and (d)
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(c) (a) and (c) - Q17 1 markThese questions consist of two statements – Assertion (A) and Reason (R). Answer these questions selecting the appropriate option given below :
Assertion (A): Carbon reduces the oxides of Sodium and Magnesium.
Reason (R): Sodium and Magnesium have more affinity for Oxygen than Carbon.
- (a)Both (A) and (R) are true and (R) is the correct explanation of (A).
- (b)Both (A) and (R) are true, but (R) is not the correct explanation of (A).
- (c)(A) is true, but (R) is false.
- (d)(A) is false, but (R) is true.
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(d) (A) is false, but (R) is true. - Q18 1 mark
Also in 31/2/1 (Q20), 31/2/2 (Q17)
These questions consist of two statements – Assertion (A) and Reason (R). Answer these questions selecting the appropriate option given below :Assertion (A): The deflection of a compass needle placed near a current carrying wire decreases when the magnitude of an electric current in the wire is increased.
Reason (R): Strength of the magnetic field at a point due to a current carrying conductor increases on increasing the current in the conductor.
- (a)Both (A) and (R) are true and (R) is the correct explanation of (A).
- (b)Both (A) and (R) are true, but (R) is not the correct explanation of (A).
- (c)(A) is true, but (R) is false.
- (d)(A) is false, but (R) is true.
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(d) (A) is false, but (R) is true. - Q19 1 markThese questions consist of two statements – Assertion (A) and Reason (R). Answer these questions selecting the appropriate option given below :
Assertion (A): The colour of clear sky appears blue.
Reason (R): Light of blue colour has longer wavelength as compared to the light of red colour so it is scattered more in the upper atmosphere.
- (a)Both (A) and (R) are true and (R) is the correct explanation of (A).
- (b)Both (A) and (R) are true, but (R) is not the correct explanation of (A).
- (c)(A) is true, but (R) is false.
- (d)(A) is false, but (R) is true.
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(c) (A) is true, but (R) is false. - Q20 1 mark
Also in 31/2/1 (Q18), 31/2/2 (Q18)
These questions consist of two statements – Assertion (A) and Reason (R). Answer these questions selecting the appropriate option given below :Assertion (A): Human female has a perfect pair of sex chromosome.
Reason (R): Sex chromosome contributed by the human male in the zygote decides the sex of a child.
- (a)Both (A) and (R) are true and (R) is the correct explanation of (A).
- (b)Both (A) and (R) are true, but (R) is not the correct explanation of (A).
- (c)(A) is true, but (R) is false.
- (d)(A) is false, but (R) is true.
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(b) Both (A) and (R) are true, but (R) is not the correct explanation of (A).
Questions 21–26 · 2 marks each
- Q21(a) 2 marksGive one example of each of the following :
- (i)Chemical reaction showing evolution of gas.
- (ii)Change in the colour of the substance during a chemical reaction.
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Zinc with dilute sulphuric acid gives hydrogen gas; an iron nail in copper sulphate solution turns the blue solution pale green.
(i) Zinc granules with dilute sulphuric acid give off hydrogen gas: . (ii) An iron nail in copper sulphate solution turns the blue solution pale green and gets a brown coat of copper: . Other correct examples also earn credit.ORQ21(b) 2 marksTranslate the following statements into chemical equations and then balance them :- (i)Hydrogen sulphide gas burns in air to give water and sulphur dioxide.
- (ii)Silver bromide on exposure to sunlight decomposes into silver and bromine.
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The balanced equations are and in sunlight.
(i) ; (ii) - Q22 2 marksName the blood vessel which brings blood to the kidneys. Why is nephron called a basic filtration unit of kidney ? Write the role of tubular part of nephron in urine formation.Step-by-step solution →
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The renal artery brings blood to the kidneys; blood is filtered in each nephron's glomerulus, and the tubule selectively reabsorbs useful substances.
The renal artery brings blood to the kidneys. The nephron is called the basic filtration unit because each kidney is made of large numbers of nephrons, and in each one blood is filtered through the glomerulus, a cluster of very thin-walled capillaries, into the cup-shaped Bowman's capsule. The tubular part selectively reabsorbs useful substances such as glucose, amino acids, salts and a major amount of water back into the blood, so that what remains flows on as urine. - Q23 2 marksMendel crossed a round and yellow seeded pea plant with a wrinkled and green seeded pea plant. What did the plants of generation look like in terms of shape and colour of seed ? On self-pollinating generation plants, plants with four types of combinations of characters were seen in generation. Write the combinations along with their ratios.Step-by-step solution →
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All seeds are round and yellow; shows four combinations in the ratio 9 : 3 : 3 : 1.
All the plants had round and yellow seeds. In the the four combinations appeared in the ratio round yellow : round green : wrinkled yellow : wrinkled green . - Q24 2 marks
Also in 31/2/1 (Q25), 31/2/2 (Q25)
Use Ohm’s law to determine the potential difference across the resistor in the circuit shown in the following diagram when key is closed :Step-by-step solution →Show answer
The potential difference across the resistor is 1 V.
The resistors are in series, so and the current is A. By Ohm's law, the potential difference across the resistor is V. - Q25(a) 2 marksA person suffering from an eye defect uses lenses of power D. Name the defect of vision and list its two causes. State the nature (converging/diverging) of the corrective lens.Step-by-step solution →
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Myopia; caused by an over-curved eye lens or an elongated eyeball; corrected by a concave (diverging) lens.
The defect is myopia (near-sightedness). Its two causes are (i) excessive curvature of the eye lens and (ii) elongation of the eyeball. The corrective lens has m, so it is a concave, that is diverging, lens.ORQ25(b) 2 marksWhat is presbyopia ? Name the type of lenses used for the correction of this defect. State the nature (converging/diverging) of the upper part of such lenses.Step-by-step solution →Show answer
An age-related loss of accommodation; corrected by bifocal lenses whose upper part is concave (diverging).
Presbyopia is the defect in which the power of accommodation of the eye decreases with age: the near point recedes and nearby objects cannot be seen clearly without glasses, because the ciliary muscles weaken and the eye lens becomes less flexible. It is corrected with bifocal lenses. The upper part of a bifocal lens is concave, that is diverging, and helps distant vision; the lower part is convex and helps near vision. - Q26 2 marks
Also in 31/2/1 (Q26), 31/2/2 (Q26)
Name the term used for the materials which cannot be broken down by biological processes. Give two ways by which they harm various components of an ecosystem.Step-by-step solution →Show answer
They are called non-biodegradable substances; they persist and pollute soil and water, and some, like pesticides, magnify along food chains.
Such materials are called non-biodegradable substances. Two ways in which they harm the components of an ecosystem: (1) They are not broken down by decomposers, so they persist in the environment for a long time and accumulate in the soil and in water bodies, polluting them. (2) Some of them, such as pesticides, enter food chains through plants and, being non-degradable, get accumulated progressively at each trophic level (biological magnification), so organisms at the higher trophic levels, including human beings, receive the highest concentration.
Questions 27–33 · 3 marks each
- Q27 3 marks
- (a)Sodium metal is stored under kerosene oil. Why ?
- (b)Some metal oxides are soluble in water. What are the aqueous solutions of these oxides called ? Write one example of such a solution.
- (c)At ordinary temperature the surface of metals such as magnesium, aluminium, zinc etc. is covered with a thin layer. What is the composition of this layer ? State its importance.
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Sodium is kept in kerosene to cut it off from air; soluble oxides give alkalis; the surface layer is oxide, which protects the metal.
(a) Sodium is highly reactive: it reacts vigorously with the oxygen and moisture of the air and can catch fire, so it is kept immersed in kerosene, with which it does not react, to cut it off from air and prevent accidents. (b) The aqueous solutions of soluble metal oxides are called alkalis; for example, sodium oxide dissolves to give sodium hydroxide solution, . (c) The thin layer is the oxide of the metal, for example on aluminium, formed by reaction with the oxygen of the air; it protects the metal from further oxidation. - Q28 3 marks
Also in 31/2/1 (Q27)
It is observed that Calcium on reaction with water floats on its surface. Explain why it happens. Also write a balanced chemical equation for the reaction that occurs. What happens when the aqueous solution of the product of this reaction reacts with Carbon dioxide gas ? Write a balanced chemical equation for the reaction.Step-by-step solution →Show answer
Hydrogen bubbles stick to calcium and make it float; carbon dioxide turns the lime water milky by forming insoluble calcium carbonate.
Calcium reacts with water to form calcium hydroxide and hydrogen gas: . It floats because the bubbles of hydrogen gas formed stick to the surface of the metal and buoy it up. When carbon dioxide reacts with the aqueous solution of calcium hydroxide (lime water), the solution turns milky because white calcium carbonate, which is insoluble in water, is formed: . - Q29 3 marks
- (a)List any two contraceptive methods practised only by women. Mention how these methods work.
- (b)Write the two roles performed by testes in human males.
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Oral pills stop release of eggs and blocked fallopian tubes stop the egg reaching the uterus; the testes make sperms and secrete testosterone.
(a) (i) Oral contraceptive pills: they change the hormonal balance of the body so that eggs are not released, so fertilisation cannot occur. (ii) Surgical blocking of the fallopian tubes: the egg cannot reach the uterus, so fertilisation does not take place. A copper-T placed in the uterus, or a covering worn in the vagina that stops sperms reaching the egg, also earns credit. (b) The testes (i) produce sperms, the male germ cells, and (ii) secrete the male hormone testosterone, which regulates sperm formation and brings about the changes seen in boys at puberty. - Q30(a) 3 marks
Also in 31/2/1 (Q29(a)), 31/2/2 (Q27(a))
Give reasons for the following :- (i)Alveoli in lungs are richly supplied with blood capillaries.
- (ii)Respiratory pigment in the blood takes up oxygen and not carbon dioxide.
- (iii)During anaerobic respiration, a 3-carbon molecule is formed as an end product instead of in human beings.
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Capillaries give alveoli a large exchange surface; haemoglobin binds oxygen strongly; without oxygen, pyruvate becomes lactic acid, not carbon dioxide.
(i) Alveoli are the sites where gases are exchanged: oxygen from the alveolar air passes into the blood and carbon dioxide from the blood passes into the alveoli. The rich network of blood capillaries in their thin walls provides a large surface for this exchange, making it quick and efficient. (ii) The respiratory pigment, haemoglobin, has a very high affinity for oxygen, so it takes up oxygen in the lungs and carries it to the tissues; carbon dioxide is more soluble in water than oxygen and is mostly transported in the dissolved form in the blood. (iii) In human muscle cells, when there is a lack of oxygen, the pyruvate (a 3-carbon molecule) formed from glucose is converted into lactic acid, which is also a 3-carbon molecule, instead of being broken down into carbon dioxide and water; that complete break-down needs oxygen and takes place in the mitochondria.ORQ30(b) 3 marksAlso in 31/2/1 (Q29(b)), 31/2/2 (Q27(b))
- (i)Name the movements that occur all along the gut in human digestive system. How do they help in digestion ?
- (ii)Where is bile juice stored in human body ? List two roles of bile juice.
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Peristalsis pushes food along the gut; bile, stored in the gall bladder, makes food alkaline and emulsifies fats.
(i) The movements are peristaltic movements (peristalsis): rhythmic contractions of the muscles lining the alimentary canal, occurring all along the gut. They push the food forward in a regulated manner, so that it is processed properly in each part of the canal, and they help to mix the food with the digestive juices. (ii) Bile juice is made in the liver and stored in the gall bladder. Two roles of bile: (1) it makes the acidic food coming from the stomach alkaline, so that the pancreatic enzymes can act on it; (2) its bile salts break large fat globules into smaller globules (emulsification), increasing the efficiency of the enzymes that digest fats. - Q31(a) 3 marks
Also in 31/2/1 (Q31(a))
Define the term power of accommodation of human eye. Write the name of the part of eye which plays a major role in the process of accommodation and explain what happens when human eye focuses- (i)nearby objects and
- (ii)distant objects.
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Power of accommodation is the eye lens's ability to change focal length; the ciliary muscles contract for near objects and relax for distant ones.
Power of accommodation is the ability of the eye lens to adjust its focal length so that both nearby and distant objects are focused on the retina. The ciliary muscles play the major role: they change the curvature, and hence the focal length, of the flexible eye lens. (i) Nearby objects: the ciliary muscles contract, the curvature of the eye lens increases and it becomes thicker, so its focal length decreases and the image of the nearby object forms on the retina. (ii) Distant objects: the ciliary muscles relax, the eye lens becomes thin, so its focal length increases and the image of the distant object forms on the retina.ORQ31(b) 3 marksAlso in 31/2/1 (Q31(b))
Draw a ray diagram to show the formation of a rainbow in the sky. On this diagram mark A – where dispersion of light occurs, B – where internal reflection of light occurs and C – where refraction of light occurs. List two necessary conditions to observe a rainbow.Step-by-step solution →Show answer
The ray is refracted and dispersed at A, internally reflected at B and refracted at C; the Sun must be behind the observer.
Ray diagram: a ray of white sunlight enters the upper part of a raindrop; at A it is refracted and dispersed into its colours (violet bent the most, red the least); the coloured rays are reflected internally at the back of the drop at B; they are refracted again at C as they leave the drop and travel towards the observer. Two necessary conditions to observe a rainbow: (1) the Sun must be behind the observer, since a rainbow is always formed in the direction opposite to the Sun; (2) water droplets, such as raindrops just after a rain shower, must be present in the air in front of the observer. - Q32 3 marksDefine the term solenoid. Draw the pattern of magnetic field lines around a current carrying solenoid. State how this magnetic field can be used to magnetise a piece of magnetic material, like soft iron.Step-by-step solution →
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A solenoid is a closely wound coil; its field is like a bar magnet's, and soft iron inside it becomes an electromagnet.
A solenoid is a coil of many circular turns of insulated copper wire wrapped closely in the shape of a cylinder. Its magnetic field lines are like those of a bar magnet: inside the solenoid they are parallel straight lines, showing a uniform field directed from the S end to the N end, and outside they leave the N end and curve round to enter the S end (see the figure). To magnetise a piece of soft iron, place it inside the solenoid and pass a current through the coil; the strong magnetic field inside magnetises it, and it becomes an electromagnet. - Q33 3 marks
Also in 31/2/1 (Q33), 31/2/2 (Q33)
Use of pesticides to protect our crops affect organisms at various trophic levels especially human beings. Name the phenomenon involved and explain how does it happen.Step-by-step solution →Show answer
Biological magnification: non-degradable pesticides enter the food chain and build up at each trophic level, reaching the maximum in human beings.
The phenomenon is biological magnification. Pesticides used on crops are washed down into the soil or into water bodies. From the soil and water they are absorbed by plants along with water and minerals, and from water bodies they are taken up by aquatic plants and animals — this is how they enter the food chain. As these chemicals are not degradable, they get accumulated progressively at each trophic level, since each organism takes in the chemical from all the food it eats from the level below. Human beings occupy the top level in the food chain, so the maximum concentration of these chemicals gets accumulated in our bodies.
Questions 34–36 · 5 marks each
- Q34(a) 5 marks
Also in 31/2/1 (Q35(a)), 31/2/2 (Q36(a))
(i) Distinguish between hormonal co-ordination in plants and animals. (ii) Which part of the brain is responsible for –- (1)intelligence
- (2)riding a bicycle
- (3)vomiting
- (4)controlling hunger (iii) How is brain and spinal-cord protected against mechanical injuries ?
Step-by-step solution →Show answer
Plant hormones lack glands while animal hormones come from endocrine glands; cerebrum, cerebellum, medulla and hypothalamus control the four activities; cranium and backbone protect.
(i) Plants: hormones are made by cells in particular regions, such as auxin at the shoot tip, with no special glands. Animals: hormones are made by specialised endocrine glands, such as the pituitary, thyroid and adrenal glands. Plants: the hormones diffuse from cell to cell to the area where they act. Animals: the hormones are secreted directly into the blood and carried to target organs. Plants: they mainly control growth and development, so the responses are slow. Animals: they control growth, metabolism, reproduction and quick responses to emergencies, work with the nervous system, and are regulated by feedback mechanisms. (ii) (1) Intelligence: cerebrum (fore-brain); (2) Riding a bicycle: cerebellum (hind-brain); (3) Vomiting: medulla (hind-brain); (4) Controlling hunger: hypothalamus (fore-brain). (iii) The brain lies inside a bony box, the cranium (skull), and within it is enclosed in fluid-filled membranes that absorb shocks. The spinal cord is protected by the vertebral column (backbone), which surrounds it.ORQ34(b) 5 marksAlso in 31/2/1 (Q35(b)), 31/2/2 (Q36(b))
(i) What are tropic movements ? Give an example of a plant hormone which- (1)inhibits growth and
- (2)promotes cell division. (ii) Explain directional movement of a tendril in pea plant in response to touch. Name the hormone responsible for this movement.
Step-by-step solution →Show answer
Tropic movements are directional growth responses to a stimulus; abscisic acid inhibits growth, cytokinin promotes cell division, and auxin makes the pea tendril coil.
(i) Tropic movements are directional growth movements of a plant part in response to a stimulus such as light, gravity, water, chemicals or touch: the part grows towards the stimulus (positive) or away from it (negative), as when a shoot bends towards light. (1) A hormone that inhibits growth: abscisic acid. (2) A hormone that promotes cell division: cytokinin. (ii) The tendrils of a pea plant are sensitive to touch. When a tendril touches a support, the part in contact with the support grows more slowly than the part away from it. The faster growth of the far side makes the tendril curl towards the support, circle round it and cling to it. The hormone responsible for this movement is auxin. - Q35 5 marks
Also in 31/2/1 (Q36), 31/2/2 (Q34)
- (a)Upper half of a convex lens is covered with a black paper. Draw a ray diagram to show the formation of image of an object placed at a distance of from such a lens. Mention the position and nature of the image formed. State the observable difference in the image obtained if the lens is uncovered. Give reason to justify your answer.
- (b)An object is placed at a distance of 30 cm from the optical centre of a concave lens of focal length 15 cm. Use lens formula to determine the distance of the image from the optical centre of the lens.
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(a) Image at , real, inverted, same size but dimmer; brighter when uncovered. (b) cm.
(a) With the upper half covered, only rays passing through the lower half form the image; in the ray diagram the ray from the top of the object through emerges parallel to the axis and meets a second ray through the lower half at . Position: at , on the other side of the lens. Nature: real, inverted and of the same size as the object; the image is complete but less bright. If the lens is uncovered, the image is formed at the same place with the same size and nature, but it is brighter. Reason: every part of a lens forms a complete image, because rays from each point of the object pass through all parts of the lens and meet at the same image point; covering half the lens only cuts down the amount of light reaching the image. (b) cm and cm, so and cm. The image is 10 cm from the optical centre, on the same side as the object (virtual, erect and diminished, ). - Q36(a) 5 marks
Also in 31/2/1 (Q34(a)), 31/2/2 (Q35(a))
- (i)Give reason why carbon can neither form cations nor anions but form covalent compounds.
- (ii)What is homologous series of carbon compound ? Write the molecular formula of any two consecutive members of homologous series of aldehydes.
- (iii)Draw the structure of the molecule of cyclohexane ().
Step-by-step solution →Show answer
Carbon shares its four valence electrons; and are consecutive aldehydes; cyclohexane is a ring of six carbon atoms with single bonds.
(i) Carbon (atomic number 6, configuration 2, 4) has four valence electrons. To form it would have to gain four electrons, and it would be difficult for a nucleus with six protons to hold ten electrons; to form it would have to lose four electrons, which needs a large amount of energy and would leave six protons holding only two electrons. Carbon therefore shares its four valence electrons with other atoms and forms covalent bonds, so its compounds are covalent. (ii) A homologous series is a series of carbon compounds with the same functional group and the same general formula, in which successive members differ by a unit (14 u); the members have similar chemical properties and show a gradation in physical properties. Two consecutive aldehydes: methanal, (molecular formula ), and ethanal, (molecular formula ). (iii) Cyclohexane, : six carbon atoms joined in a ring by single bonds, each carbon also bonded to two hydrogen atoms, as drawn in the structure.ORQ36(b) 5 marksAlso in 31/2/1 (Q34(b)), 31/2/2 (Q35(b))
(i) Name a commercially important carbon compound having functional group and write its molecular formula. (ii) Write chemical equation to show its reaction with- (1)Sodium metal
- (2)Excess conc. sulphuric acid
- (3)Ethanoic acid in the presence of an acid catalyst
- (4)Acidified potassium dichromate Also write the name of the product formed in each case.
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Ethanol () gives sodium ethoxide, ethene, ethyl ethanoate and ethanoic acid with sodium, conc. sulphuric acid, ethanoic acid and dichromate.
(i) Ethanol (ethyl alcohol); molecular formula (that is, ). (ii) (1) ; product: sodium ethoxide (and hydrogen gas). (2) ; product: ethene. (3) ; product: ethyl ethanoate (an ester). (4) ; product: ethanoic acid.
Questions 37–39 · 4 marks each
- Q37 4 marks
Also in 31/2/1 (Q38), 31/2/2 (Q39)
Asexual reproduction involves a single parent to produce offsprings without the formation of gametes. It occurs by the following ways : Fission, Budding, Fragmentation, Spore formation and Regeneration. In one of the methods like regeneration, Planaria A is cut horizontally into three pieces – L, M and N and Planaria B is cut vertically into two equal halves – O and P.- (a)Which of the cut pieces of the two Planaria could regenerate to form a complete organism ?[1]
- (b)Give an example of another organism which follows the same mode of reproduction as Planaria.[1]
- (c)(i)What is the meaning of ‘development’ in regeneration ?[2]
- (c)(ii)OR : Differentiate between regeneration and fragmentation.[2]
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All pieces (L, M, N, O, P) regenerate; Hydra is another example; development is the organised sequence of changes forming the lost parts.
(a) All the pieces: L, M and N of Planaria A, and O and P of Planaria B, can each regenerate into a complete organism. (b) Hydra. (c)(i) In regeneration, specialised cells in the cut piece divide and make a large number of cells. From this mass of cells, different cells change into the various cell types and tissues of the missing parts. These changes take place in an organised sequence, and this organised sequence of changes is called development. OR (c)(ii) Regeneration: occurs in fully differentiated organisms (Hydra, Planaria) when the body is cut or broken; specialised cells divide and develop into the lost parts; it is not the normal way these organisms reproduce. Fragmentation: occurs in simple multicellular organisms (Spirogyra); the body breaks up into pieces by itself on maturing, and each piece simply grows by cell division into a new individual; it is a normal method of reproduction. - Q38 4 marks
Also in 31/2/1 (Q39), 31/2/2 (Q37)
When electric current flows in a purely resistive circuit electrical energy gets fully converted into heat energy. The amount of heat produced () in the circuit is found to be directly proportional to- (i)the square of current ()
- (ii)the resistance () of the conductor and
- (iii)the time () for which current flows. In other words . Electrical devices such an electric fuse, electric heater, electric iron etc. are all based on this effect called heating effect of electric current.
- (a)List two properties of heating elements.[1]
- (b)List two properties of electric fuse.[1]
- (c)(i)Name the principle on which an electric fuse works. Explain how a fuse wire is capable of saving electrical appliances from getting damaged due to accidently produced high currents.[2]
- (c)(ii)OR : The power of an electric heater is 1100 W. If the potential difference between the two terminals of the heater is 220 V, find the current flowing in the circuit. What will happen to an electric fuse of rating 5 A connected in this circuit ?[2]
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Heating elements need high resistivity and melting point; a fuse uses the heating effect to break the circuit; or the heater draws A.
(a) A heating element should have (1) a high resistivity, so that the heat is produced mainly in the element, and (2) a high melting point, so that it stays red-hot without melting; it should also not oxidise readily at high temperatures. (b) An electric fuse wire has (1) a low melting point and (2) a high resistance per unit length, being much thinner than the connecting wires that carry the same current, so that the heat produced by an excess current is concentrated in the fuse and quickly raises it to its melting point. It is connected in series with the appliance, in the live wire, and has a definite current rating (such as 1 A, 2 A, 3 A, 5 A or 10 A). (c)(i) A fuse works on the heating effect of electric current (Joule's law of heating, ). It is connected in series with the appliance, so the whole current flows through it. When an unduly high current flows, the heat produced in the fuse wire rises sharply (as ), the wire reaches its melting point and melts, and the circuit is broken before the high current can damage the appliance. OR (c)(ii) A. The fuse is rated 5 A and melts only if the current is more than 5 A, so it will not melt and the heater works normally; the fuse is then working at its limit, and any rise in the current above 5 A would melt it. - Q39 4 marks
Also in 31/2/1 (Q37), 31/2/2 (Q38)
Salts play a very important role in our daily life. Sodium chloride which is known as common salt is used almost in every kitchen. Baking soda is also a salt used in faster cooking as well as in baking industry. The family of salts is classified on the basis of cations and anions present in them.- (a)Identify the acid and base from which Sodium chloride is formed.[1]
- (b)Find the cation and the anion present in Calcium sulphate.[1]
- (c)(i)“Sodium chloride and washing soda both belong to the same family of salts.” Justify this statement.[2]
- (c)(ii)OR : Define the term pH scale. Name the salt obtained by the reaction of Potassium hydroxide and Sulphuric acid and give the pH value of its aqueous solution.[2]
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and form sodium chloride; calcium sulphate has and ; sodium chloride and washing soda share .
(a) Sodium chloride is formed from hydrochloric acid, , and sodium hydroxide, : . (b) Cation: calcium ion, ; anion: sulphate ion, . (c)(i) Salts having the same positive or the same negative ion belong to one family. Sodium chloride (, ) and washing soda, (, ), have the same cation, , so both belong to the family of sodium salts. OR (c)(ii) The pH scale is a scale for measuring the hydrogen ion concentration in a solution, from 0 (very acidic) to 14 (very alkaline), with 7 as neutral. : the salt is potassium sulphate. It is the salt of a strong acid and a strong base, so its aqueous solution is neutral, .