Draw a parallelogram ABCD in which BC = 5 cm, AB = 3 cm and \angle ABC = 60^\circ, divide it into triangles B…

Draw a parallelogram ABCD in which $BC=5$ cm, $AB=3$ cm and $\angle ABC=60^{\circ }$, divide it into triangles BCD and ABD by the diagonal BD. Construct the triangle BD'C' similar to $△BDC$ with scale factor $\frac{4}{3}$. Draw the line segment D'A' parallel to DA where A' lies on extended side BA. Is A'BC'D' a parallelogram?